Answer:
0.00665
0.006951
Step-by-step explanation:
If the first child is born with the affliction, there's a 0.05 probability that the second child will be born with the affliction. Which means there's a 0.95 probability that they won't.
The probability that the first child is born with the affliction but not the second is therefore:
P = 0.007 × 0.95
P = 0.00665
There's a 0.007 probability that the first child will be born with the affliction, which means there's a 0.993 probability that they won't. If the first child isn't born with the affliction, then the probability the second child will have it is 0.007.
So the probability that the first child is not born with the affliction and the second child is would be:
P = 0.993 × 0.007
P = 0.006951
So even just multiplying 3x2 by 6x we know it has to be D because it’s the inly one with 18x3 but i went ahead and worked out the whole problem using the box method
it’s in the attached picture
.6 as 5x2=10 and you have to do the same to 3 so 3x2=6
