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3 years ago

A quadratic function in vertex form whose graph has a vertex of (-4,6) and passes through the point (-1,9)

Mathematics

1 answer:

scZoUnD [109]3 years ago

7 0

Couldnt you just do the X's together and the Y's and your answer after you divide by each??

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With a slope of m = -2 and a point being (5,-2) what’s the Y-intercept?

almond37 [142]

Answer:

c = 8

Step-by-step explanation:

Given the following data;

Slope, m = -2

Points (x, y) = (5, -2)

To find the intercept, c;

Equation of a straight line is given by the formula: y = mx + c

Where;

m is the slope.

x and y are the points

c is the intercept.

Substituting the values in order to find the intercept, we have;

-2 = -2(5) + c

-2 = -10 + c

c = 10 - 2

c = 8

Therefore, the y-intercept is 8.

3 0

3 years ago

Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4

vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

$c^2 = 4^2 + 6^2$

$c^2 = 16 + 36$

$c^{2}$ = 52

Pythagoras' theorem for the middle one :

$b^{2}$ = $6^{2}$ + $a^{2}$

Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

$16 + 8a + a^2 = 52 + 6^2 + a^2$

$16 + 8a = 52 + 6^2$

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

$a = \frac{72}{8}$

a = 9

Verifying :

$b^2 = 6^2 + a^2$

$b^2 = 36 + 81$

$b^2 = 117$

$b^{2}$ = 117

The biggest one :

$(4+a)^2 = c^2 + b^2$

$(4+9)^2 = 52 + 117$

$13^2 = 169$

True

8 0

2 years ago

How to do the problem

marta [7]

There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
$8 \frac{1}{4} + 9 \frac{1}{4} + 8 \frac{7}{8} + 9 \frac{5}{8} + 10 \frac{3}{4}$
$= \frac{8 \times 4 + 1}{4} + \frac{9 \times 4 + 1}{4} \\ + \frac{8 \times 8 + 7}{8} + \frac{9 \times 8 + 5}{8} \\ + \frac{10 \times 4 + 3}{4}$
$= \frac{33}{4} + \frac{37}{4} + \frac{71}{8} + \frac{77}{8} + \frac{43}{4} \\ = \frac{33 \times 2}{4 \times 2} + \frac{37 \times 2}{4 \times 2} + \frac{71}{8} \\ + \frac{77}{8} + \frac{43 \times 2}{4 \times 2}$
$= \frac{66 + 74 + 71 + 77 + 86}{8}$
$= \frac{374}{8} = \frac{186}{4}$
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
$\frac{186 - 153}{4} = \frac{33}{4} = 8 \frac{1}{4}$

The leftover watermelon is 8 & 1/4 pounds.

6 0

2 years ago

HELP PLEASE

Ksju [112]

((800+100+400+35)÷3,250)×100
=41%

3 0

2 years ago

Read 2 more answers

Solve the system of equations by elimination and identify which could be a first step of the elimination method for the system.

Alecsey [184]

3x+2y=24
Times 2
6x+4y=48
-
6x+2y=30
=
2y=18
y=9
x=2. Hope it help!

4 0

3 years ago