Question

Can anyone help me please??? It’s not online. And please keep scrolling if u don’t know ...

Answer 1

Answer:

Step-by-step explanation:

slopes and equations:

find the  equation thur ( 6,1 )  and (-2,-3)

find the slope m

m = (y2-y1) / (x2-x1 )

m = (-3 - 1) / (-2 -6)

m = -4 / -8

m = 1/2

now use the point-slope formula with our known slope

y-y1 = m(x-x1)

y-1 = 1/2(x-6)

y - 1 = 1/2x -3

y = 1/2x -3 +1

y = $\frac{1}{2}$x -2

Find the equation parallel to y = 3x + 6 and thur (0,1)

Parallel means the same slope, the slope is 3 for the equation above.

use the slope-intercept formula again with the point given and the slope 3

y-1 = 3(x -0)

y - 1 = 3x

y = 3x +1

Find the equations perpendicular to 2x + y = 8 and the same y intercept as  4y = x + 3.

put both equations into proper form

y = -2x +6

y = $\frac{1}{4}$x + $\frac{3}{4}$

perpendicular means  reciprocal slope and change the sign, the 2nd equation has an intercept of  $\frac{3}{4}$ , so

y = 1/2x + $\frac{3}{4}$

there you go Amanda  :)