Answer:
93.5 square units
Step-by-step explanation:
Diameter of the Circle = 12 Units
Therefore:
Radius of the Circle = 12/2 =6 Units
Since the hexagon is regular, it consists of 6 equilateral triangles of side length 6 units.
Area of the Hexagon = 6 X Area of one equilateral triangle
Area of an equilateral triangle of side length s = 
Side Length, s=6 Units

Area of the Hexagon

Answer:
$14
Step-by-step explanation:
Make the variables:
x
x + 3
2x + 3 = 25
2x = 22
x = 11
11, 14
G=38
Whenever you divide or multiply by one the number stays the same, therefore just take out all the xs and then solve the equation. I hope this helps!
Shifting a graph up by c units involves adding c to the whole function
therefor
y=ax^2+c is c units higher than y=ax^2 (aka, it is shifted c units up)