Answer:
The worth of boat in 2013 will be $9202.6
Step-by-step explanation:
Rate of depreciation = 9% = 0.09
Cost of Boat in 2006 =$ 17,800
Cost of Boat in 2013 = ?
Years = 2013-2006= 7 years
The formula used is: 
Since the value of boat is depreciating the value of r will be r=-0.09
Here P = 17,800 , r=-0.09 and t = 7 years Finding A
So, the worth of boat in 2013 will be $9202.6
Answer:
Step-by-step explanation:
The number of samples is large(greater than or equal to 30). According to the central limit theorem, as the sample size increases, the distribution tends towards normal. The formula is
z = (x - µ)/(σ/√n)
Where
x = sample mean
µ = population mean
σ = population standard deviation
n = number of samples
From the information given,
µ = 22199
σ = 5300
n = 30
the probability that a senior owes a mean of more than $20,200 is expressed as
P(x > 20200)
Where x is a random variable representing the average credit card debt for college seniors.
For n = 30,
z = (20200 - 22199)/(5300/√30) =
- 2.07
Looking at the normal distribution table, the probability corresponding to the z score is 0.0197
P(x > 20200) = 0.0197
If the points P, Q and R are collinear, then a slope of line PQ and a slope of line QR are equal.
The formula of a slope:
PQ → (0, 3), (2, 0).
Substitute:
QR → (2, 0), (4, -3).
Substitute:
CORRECT :)
<h3>Answer: m = -1.5.</h3>
The median is 4 because 2 x’s out 9, 3 x’s out 7, 3 x’s out 5, and 4 is the only remaining number.
