ax² + bx + c = 0
x = (-b ± √(b² - 4ac))/2a
First, rewrite the first equation so that the first coefficient is 1. Divide everything by a.
(ax² + bx + c = 0)/a =
x² + (b/a)x + (c/a) = 0
Isolate (c/a) by subtracting (c/a) from both sides
x² + (b/a)x + (c/a) (-(c/a) = 0 (- (c/a)
x² + (b/a)x = 0 - (c/a)
Add spaces
x² + (b/a)x = -c/a
Take 1/2 of the middle term's coefficient and square it. Remember that what you add to one side, you add to the other.
x² + (b/a)x + (b/2a)² = -c/a + (b/2a)²
Simplify the left side of the equation.
x² + (b/a)x + (b/2a)² = (x + (b/2a))²
(x + b/2a))² = ((b²/4a²) - (4ac/4a²)) -> ((b² - 4ac)/(4a²))
Take the square root of both sides of the equation
√(x + b/2a))² = √((b²/4a²) - (4ac/4a²))
x + b/(2a) = (±√(b² - 4ac)/2a
Simplify. Isolate the x.
x = -(b/2a) ± (∛b² - 4ac)/2a = (-b ± √(b² - 4ac))/2a
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Answer:
3927 cm² wrapping paper will be required.
Step-by-step explanation:
Lateral surface area of a cone shaped wrapper = πrl
where, r = radius of the waffle cone
and l = slant height of the cone
It has been given in the question, radius 'r' = 5cm
and lateral height 'l' = 10 cm
Lateral surface area of the cone = π(5)(10)
= 50π
= 157.08 cm²
If they plan to make 25 waffles then wrapper paper required
= 25×157.08
= 3927 cm²
Therefore, 3927 cm² wrapping paper will be required.
The answer is c
1/6 divided by 1/2
i had this question on my own
Answer:
1/6a-1/6
Step-by-step explanation:
-2/3 transferred into 6th's is -4/6. You combine like terms, -4/6a+5/6a=1/6a
Then since -1/6 doesn't have a like term, it stays the same.
Answer:
150
Step-by-step explanation:
S.A.=2(wl+hl+hw)=
2((3x9)+(4x3)+(4x9))
2(27+12+36)
2(75)
150
