Answer:
2 and 6 for the circles.
-18 for the square.
Step-by-step explanation:
-3 times a number is -6.
The number is 2.
2 times a number is 12.
The number is 6.
6 times -3.
The number is -18.
No solution / no x
D=b^2-4*a*c -> D=-4^2-4*1*21 -> D=-28 -> D<0, no solution
3$
Step-by-step explanation:
12$-(12$:4+12$:2)=12$-(3$+6$)=12$-9$=3$ Hope this helped!
Answer:
y= 3cb/ 5t
Step-by-step explanation:
combine 5 and t/4
5t/4 times y= 3(b/4) times c
combine 5t/4 and y
5ty/4=3(b/4) times c
combine 3 and b/4
5ty/4= 3b/4 times c
combine 3b/4 and c
5ty/4=3bc/4
multiply each term in 5ty/4=3bc/4 by 4/5t to eliminate the fractions
y=3bc/4 times 4/5t
simplify
y=3cb/5t
Answer and Step-by-step explanation:
a. The strings {a, b, c} with at least one a and at least one b.
Solution: ∑ = {a, b, c}
where
(a +b +c)(a (a +b +c)*b + b (a +b +c) a (a +b +c)*
b. The set of 0’s and 1’s string whose tenth symbol from the right end is 1.
Sol: (0+1)*1(0+1)9
c. The set of 0’s and 1’s string with at most one pair of consecutive 1’s.
sol: (0+10)(11+∑)(0+10)
