If the original population has a Normal distribution, then the distribution of the sample mean is also Normal.
If we extract random samples of size n from a population with half a μ and standard deviation σ, then the distribution of the sample mean will have the following parameters:
μ_Xbar = μ
σ_Xbar = σ/ √(n).
Where:
μ = 50
σ = 4
n = 20
So:
μ_Xbar = 50
σ_Xbar = 0.8944
Answer:
3−2
Step-by-step explanation:
1. B
2. D) 2/7 teaspoons
3. D) $.90
Answer: I: (3, +infinity) D: (-infinity, 3) (this is the fourth answer)
Step-by-step explanation: The graph is decreasing left to right until 3, and begins to increase from left to right beginning at 3.
