The answer is 2040 hope this helps
Answer:
(a) 283 days
(b) 248 days
Step-by-step explanation:
The complete question is:
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. (a) What is the minimum pregnancy length that can be in the top 11% of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths?
Solution:
The random variable <em>X</em> can be defined as the pregnancy length in days.
Then, from the provided information .
(a)
The minimum pregnancy length that can be in the top 11% of pregnancy lengths implies that:
P (X > x) = 0.11
⇒ P (Z > z) = 0.11
⇒ <em>z</em> = 1.23
Compute the value of <em>x</em> as follows:
Thus, the minimum pregnancy length that can be in the top 11% of pregnancy lengths is 283 days.
(b)
The maximum pregnancy length that can be in the bottom 5% of pregnancy lengths implies that:
P (X < x) = 0.05
⇒ P (Z < z) = 0.05
⇒ <em>z</em> = -1.645
Compute the value of <em>x</em> as follows:
Thus, the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths is 248 days.
1.44 divided by 16 which is 0.09 and to check answer you take 0.09 and multiply by 15 and you get 1.44
Answer:
The numbers are 2, 4, 6 and 8
Step-by-step explanation:
let the four numbers be x, y, z and l respectively
then:
x+y+z+l
(z+l)–6=4x
since they are all four consecutive even integers
then y=x+2
z=y+2=x+4
l=z+2=x+6
since (z+l)–6=4x
then ((x+4)+(x+6))–6=4x
2x+4=4x
4=4x–2x
4=2x
2=x