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zmey [24]
3 years ago
5

On a trip to Paris, Franco visits the Eiffel tower at 6:44 P.M. The Eiffel tower is 986 feet tall and Franco is 6 feet tall. Fra

nco casts a shadow is 38 feet long. How long is the Eiffel tower’s shadow(to the nearest foot)?
A. 6432 feet

B. 5933 feet

C. 6307 feet

D. 6245 feet


Please help me I need it a lot, thank you.
Mathematics
1 answer:
Contact [7]3 years ago
4 0

Answer:

Option D is correct.

Step-by-step explanation:

It is given that 6 feet tall casts shadow for 38 feet long.

We need to find the shadow f 986 ft tall Eiffel tower.

Let's set up proportional equation to solve. Let the shadow length as 'x' feet for the tower.

\frac{6}{38} = \frac{986}{x}

Cross multiply,

6 x= 37468

Divide both sides by 6.

x= 6244.67 feet approximately.

If we round it to nearest feet, we get 6245 feet.

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Answer:

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(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

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The information provided is:

P (A) = 0.02

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Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

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=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

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=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

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