Ask question

Ask question

All categories

GarryVolchara [31]

3 years ago

13

- 4y = - 40 please show work if you can

1 answer:

Valentin [98]3 years ago

4 0

Y = 10
-4 * 10 = 40

Hope this helps!!!:):):)

You might be interested in

Write an equation in slope-intercept form for the line that satisfies each set of conditions.

finlep [7]

Answer: Y= 2/3x + 9

Explanation: The equation is in slope-intercept form, y=mx+b. Since it is parallel to the equation, it has the same slope (2/3x) and since b is the x intercept, b is 9.

7 0

4 years ago

Rolling a Red and Yellow Dice

grandymaker [24]

Answer:

Option C 5/12 is correct option

Step-by-step explanation:

We have to find the probability that shows yellow dice has a larger value than the red dice.

Probability= total no of favorable outcomes / total no of outcomes

in our case, considering the data set, we have to find those pair where value of yellow die is greater than the red die. Where (1,2) represents 1 on the red die and 2 on the yellow die

(1,2) (1,3) (1,4) (1,5) (1,6)

(2,3) (2,4) (2,5) (2,6)

(3,4) (3,5) (3,6)

(4,5) (4,6)

(5,6)

These are the possibilities where yellow die has greater value than red die.

total no of favorable outcomes = 15

total no of outcomes = 36

probability that yellow die has greater value than red die = 15 / 36

= 5/ 12

Option C 5/12 is correct option

3 0

3 years ago

-3/5m + 8 = 20<br> what is the answer of m

horrorfan [7]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's solve ~

$\qquad \sf \dashrightarrow \: - \frac{ 3}{5} m + 8 = 20$

$\qquad \sf \dashrightarrow \: - \frac{ 3}{5} m = 20 - 8$

$\qquad \sf \dashrightarrow \: - \frac{ 3}{5} m =12$

$\qquad \sf \dashrightarrow \: - \frac{ }{} m =12 \times \frac{5}{3}$

$\qquad \sf \dashrightarrow \: - m = 4 \times 5$

$\qquad \sf \dashrightarrow \:m = - 20$

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

8 0

2 years ago

Which is the last operation performed when evaluating (8-2x)^2+4 for x=3

Salsk061 [2.6K]

Addition will be the last operation

6 0

3 years ago

Read 2 more answers

Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact

scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

$\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153$

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

$\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}$

$=\frac{(55-1)\times 94.7}{75}\\\\=68.184$

The test statistic value is, 68.184.

Decision:

$cal.\chi^{2}=68.184$

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0

3 years ago