Answer:
2x²+2x
Step-by-step explanation:
you have f(x)= x+1 and g(x)= 2x
you must multiply the 2 polynomials
(1x·2x) +( 1·2x)
1·2=2 x^1·x^1=x²
2x²
1·2x=2x
Answer:
<h2>4/3 Joules </h2>
Step-by-step explanation:
Work is said to be done when force applied to an object causes the object to move through a distance.
Work done = Force * perpendicular distance.
Given Force F = xy i + (y-x) j and a straight line (-1, -2) to (1, 2)
First we need to get the equation of the straight line given.
Given the slope intercept form y = mx+c
m is the slope
c is the intercept
m = y₂-y₁/x₂-x₁
m = 2-(-2)/1-(-1)
m = 4/2
m = 2
To get the slope we will substtutte any f the point and the slope into the formula y = mx+c
Using the point (1,2)
2 = 2+c
c = 0
y = 2x
Substituting y = 2x into the value of the force F = xy i + (y-x) j we will have;
F = x(2x) i + (2x - x) j
Using the coordinate (1, 2) as the value of s
![W = \int\limits^a_b ({2x^2 i + x j}) \, (i+2j)\\W = \int\limits^a_b ({2x^{2}+2x }) \, dx \\W = [\frac{2x^{3} }{3} +x^{2} ]\left \ x_2=1} \atop {x_1=-1}} \right.\\W = (2(1)^3/3 + 1^2) - (2(-1)^3/3 + (-1)^2)\\W =(2/3+1) - (-2/3+1)\\W = 2/3+2/3+1-1\\W = 4/3 Joules](https://tex.z-dn.net/?f=W%20%3D%20%5Cint%5Climits%5Ea_b%20%28%7B2x%5E2%20i%20%2B%20x%20j%7D%29%20%5C%2C%20%28i%2B2j%29%5C%5CW%20%3D%20%5Cint%5Climits%5Ea_b%20%28%7B2x%5E%7B2%7D%2B2x%20%7D%29%20%5C%2C%20dx%20%5C%5CW%20%3D%20%5B%5Cfrac%7B2x%5E%7B3%7D%20%7D%7B3%7D%20%2Bx%5E%7B2%7D%20%5D%5Cleft%20%5C%20x_2%3D1%7D%20%5Catop%20%7Bx_1%3D-1%7D%7D%20%5Cright.%5C%5CW%20%3D%20%282%281%29%5E3%2F3%20%2B%201%5E2%29%20-%20%20%282%28-1%29%5E3%2F3%20%2B%20%28-1%29%5E2%29%5C%5CW%20%3D%282%2F3%2B1%29%20-%20%28-2%2F3%2B1%29%5C%5CW%20%3D%202%2F3%2B2%2F3%2B1-1%5C%5CW%20%3D%204%2F3%20Joules)
2/10 of a gallon. 1/10 is half so then 1/10 times 2 would equal 2/10
Describe um it’s a line and has a F
Answer:
1.1
Step-by-step explanation:
In this image, we can see that every box, we add 0.2
From 0.1 to 0.3, we add 0.2
We continue with this pattern for the rest of the boxes
When adding decimals, you can imagine it like you are adding normal numbers, and that you are carrying extra (more than 9) to the next column in the same way.
{column/place value}
At first, it might seem like adding 0.2 to 0.9 would result in 0.11, but let's think that through a little bit more. We know that 0.1 is less than 0.2, so, it doesn't make sense for that to be the sum.
Instead, we have to carry the 11 over to the other side of the decimal. (This is because each place value is equal to 10 of the value to the right. If we add digits in the ones place that add up to 10, we carry the "1" over to the right, into the tens place.)
So, we carry the "1" from 11 to the one's place. Now, we are left with
1.1
(hope this helps!! decimals can be tricky at first)
