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madreJ [45]
3 years ago
6

PLS HELP ASAP IS FOR A TEST I REALLY NEED YALL HELP Ill mark Brainliest to correct answer

Mathematics
1 answer:
Helga [31]3 years ago
3 0

Answer:50x-4Step-by-step explanation:

1x^7+1x^5+8x^4+2x^3-4

7x+5x+32x+6x-4

50x-4

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Answer:

The coordinates of E are E(x,y) = \left(\frac{9}{2}, 0 \right).

Step-by-step explanation:

The triangle ABC represents a right triangle as both sides AB and AC are orthogonal to each other. The side AB is in the y axis, whereas the side AC is in the x axis. The triangle is dilated with respect to the origin, in which point A is set.

Vectorially speaking, dilation is defined by the following operation:

P'(x,y) = O(x,y) + k\cdot [P(x,y) - O(x,y)] (1)

Where:

O(x,y) - Point of reference.

P(x,y) - Original point.

P'(x,y) - Dilated point.

k - Dilation factor.

By applying this operation, point B becomes point D:

B(x,y) = (0,4), D(x,y) = (0,6)

D(x,y) = (0,0) + k\cdot [(0,4)- (0,0)]

D(x,y) = (0,0) + k\cdot (0,4)

(0,6) = (0,0) +(0,4\cdot k)

(0, 6) = (0,4\cdot k)

k = \frac{3}{2}

Lastly, we transform point C into point E by applying the same operation: C(x,y) = (3, 0), O(x,y) = (0,0) and k = \frac{3}{2}

E(x,y) = (0,0) + \frac{3}{2}\cdot [(3,0)-(0,0)]

E(x,y) = \left(\frac{9}{2}, 0 \right)

The coordinates of E are E(x,y) = \left(\frac{9}{2}, 0 \right).

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Answer:

448

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