This is the concept of application of quadratic expressions. Given that the height of the ball is modeled by the equation;
h=-7.3t^2+8.25t+2.1+5
The time taken for the ball to hit the ground will be given as falls;
-7.3t^2+8.25t+7.1=0
to solve for t we use the quadratic formula;
t=[-b+/-sqrt(b^2-4ac)]/(2a)
a=-7.3, b=8.25, c=2.1
t=[-8.25+/-sqrt[8.25^2+4*7.3*7.1]/(-2*7.3)
t= -0.572
or
t=1.702
since there is not negative time we take the time taken for the ball to hit the ground will be: t=1.702 sec
Answer:
3.25 :)
Step-by-step explanation:
Answer and step-by-step explanation:
I believe it is 287. I am not entirely sure, but I believe that is the answer.
Consider the function f(x<span>) = 2 x + 1. We recognize the equation y = 2 x + 1 as the Slope-Intercept form of the equation of a line with slope 2 and y-intercept (0,1). Think of a point moving on the </span>graph<span> of f. As the point moves toward the right it rises.
hope this helps
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It would be 90(4 sides)= 360 ft
or 90ft+90ft+90ft+90ft=360ft
