How would you simplify the expression represented by the diagram below?

Find the difference. express the answer in scientific notation. (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 sup

Georgia [21]

The difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

<h3>How to determine the notation</h3>

Given the expression

(5. 29 × 10^11) - (3. 86 × 10 ^11)

First, find the common factor

10^11 ( 5. 29 - 3. 86)

Then substract the values within the bracket

10^11 (1. 43)

Multiply with the factor, we have

⇒1. 43 × 10^11

Thus, the difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

Learn more about index notation here:

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7 0

2 years ago

Keep gettin those wrong. Please help!!!

larisa [96]

Answer: About 14.14 in^3

Step-by-step explanation:

We know that the circumference of a sphere is C=2πr. We are given that the circumference is 9.42 in. We can find the radius to get our volume.

$9.42=2\pi r$

$4.71=\pi r$

$r=1.5\\$

Now that we know radius, we can find our volume.

$V=\frac{4}{3} \pi r^3$

$V=\frac{4}{3} \pi (1.5)^3$

$V=14.14in^3$

5 0

4 years ago

Evaluate 5.5r8.35s when r12 and s4.

Over [174]

Answer:

32.6

Step-by-step explanation:

when you plug in for s and r you will get 66-33.4 since 5.5 multiped by 12 is 66 and 8.35 multiplied by 4 is 33.4 .

then you subtract them and that's how you'll get your answer

3 0

3 years ago

Plz help I'm just having a brain fart right now<br><br>

Wittaler [7]

Answer:

x=11

Step-by-step explanation:

For extra help the second answer is: 7a(3-a)

4 0

3 years ago

A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs

LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

$h=\frac{400}{\pi r^2}$

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: $h=\frac{400}{\pi r^2}$

Therefore:

$C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})$

$C(r)=0.12\pi r^2+\frac{24}{r}$

$C(r)=\frac{0.12\pi r^3+24}{r}$

The minimum cost occurs when the derivative of the Cost =0.

$C^{'}(r)=\frac{6\pi r^3-600}{25r^2}$

$6\pi r^3-600=0$

$6\pi r^3=600$

$\pi r^3=100$

$r^3=\frac{100}{\pi}$

$r^3=31.83$

r=3.17 cm

Recall that:

$h=\frac{400}{\pi r^2}$

$h=\frac{400}{\pi *3.17^2}$

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0

3 years ago