What is-2 |x+7| + 3 =19
2 answers:
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Explanation:
Each row in Pascal's triangle is a listing of the values of nCk = n!/(k!(n-k)!) for some fixed n and k in the range 0 to n. nCk is <em>the number of combinations of n things taken k at a time</em>.
If you consider what happens when you multiply out the product (a +b)^n, you can see where the coefficients nCk come from. For example, consider the cube ...
(a +b)^3 = (a +b)(a +b)(a +b)
The highest-degree "a" term will be a^3, the result of multiplying together the first terms of each of the binomials.
The term a^b will have a coefficient that reflects the sum of all the ways you can get a^b by multiplying different combinations of the terms. Here they are ...
- (a +_)(a +_)(_ +b) = a·a·b = a^2b
- (a +_)(_ +b)(a +_) = a·b·a = a^2b
- (_ +b)(a +_)(a +_) = b·a·a = a^2b
Adding these three products together gives 3a^2b, the second term of the expansion.
For this cubic, the third term of the expansion is the sum of the ways you can get ab^2. It is essentially what is shown above, but with "a" and "b" swapped. Hence, there are 3 combinations, and the total is 3ab^2.
Of course, there is only one way to get b^3.
So the expansion of the cube (a+b)^3 is ...
(a +b)^3 = a^3 + 3a^2b +3ab^2 +b^3 . . . . . with coefficients 1, 3, 3, 1 matching the 4th row of Pascal's triangle.
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In short, the values in Pascal's triangle are the values of the number of combinations of n things taken k at a time. The coefficients of a binomial expansion are also the number of combinations of n things taken k at a time. Each term of the expansion of (a+b)^n is of the form (nCk)·a^(n-k)·b^k for k =0 to n.
The total number of ways by words are formed is 35 ways.
According to the statement
We have given that the 5 letters and we have to make word from them and the letters are repeated as equal to letters in given words.
And we have to find the possible ways.
So, The given words are:
TEXAS and MEXICO
Here X = 2 and E = 2 and all other words are one time used words.
We can find possible ways by use of combination and permutation.
So,
Total number of ways =
here 3 because three letters are not repeatable and 2 letters are repeated for 2 times.
So,
Total number of ways =
Total number of ways =
Total number of ways =
Total number of ways = 15 + 20
Total number of ways = 35.
So, The total number of ways by letters are formed is 35 ways.
Learn more about combination and permutation here
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