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Answer 1

$\bf \begin{cases} V_1=\frac{1}{2}\left( \frac{4}{3}\pi\cdot x\cdot r_1^3 \right) \\\\ V_1=12\cdot \pi \cdot x\cdot r_2^2\\ --------------\\ V_1=V_2 \\\\ \frac{1}{2}\left( \frac{4}{3}\pi\cdot x\cdot r_1^3 \right)=12\cdot \pi \cdot x\cdot r_2^2 \end{cases} \\\\\\ \cfrac{1}{2}\left( \frac{4}{3}\pi\cdot x\cdot r_1^3 \right)=12\cdot \pi \cdot x\cdot r_2^2\implies \cfrac{2\pi x}{3}r_1^3=12\pi xr_2^2$

$\bf r_1^3=\cfrac{3}{2\pi x}\cdot 12\pi x r_2^2\implies r_1^3=\cfrac{3}{1}\cdot 6r_2^2 \\\\\\ r_1^3=18r_2^2\impliedby \textit{now, taking }\sqrt[3]{\qquad }\textit{ to both sides} \\\\\\ \sqrt[3]{r_1^3}=\sqrt[3]{18r_2^2}\implies r_1=\sqrt[3]{18r_2^2}$