Answer: 220 miles
Step-by-step explanation:
Let's write the equations for each case:
A Hertz Rent-a Car:
Charges a fixed amount of $40, plus a $0.10 per mile.
Then if you drive x miles, we get a total cost of:
C(x) = $40 + $0.10*x
Enterprise Rent-A-Car:
Chares a fixed amount of $18 plus $0.20 per mile, so if you drive x miles, the cost is:
K(x) = $18 + $0.20*x
Now, we want to find how many miles you can drive such that you would pay the same in both companies.
Then we need to find x such that:
C(x) = K(x)
$40 + $0.10*x = $18 + $0.20*x
Let's solve this for x.
$40 - $18 = $0.20*x - $0.10*x
$22 = ($0.20 - $0.10)*x
$22 = $0.10*x
$22/$0.10 = x
220 = x
So if you drive exactly 220 miles, you would pay the same in both companies.
It seem like there are information missing on the question posted. Let
me answer this question with all I know. So here is what I believe the
answer is, handle. i think this is right??
Answer:
38 farenheight is higher as 2 c= 35 farenheight
Step-by-step explanation:
Answer:
i think c
Step-by-step explanation:
Answer:
![h = 162.0\ cm](https://tex.z-dn.net/?f=h%20%3D%20162.0%5C%20cm)
Step-by-step explanation:
Given
![BSA = \frac{\sqrt{w*h}}{60}](https://tex.z-dn.net/?f=BSA%20%3D%20%5Cfrac%7B%5Csqrt%7Bw%2Ah%7D%7D%7B60%7D)
Required
Find h, when BSA = 1.5 and w = 50
We have:
![BSA = \frac{\sqrt{w*h}}{60}](https://tex.z-dn.net/?f=BSA%20%3D%20%5Cfrac%7B%5Csqrt%7Bw%2Ah%7D%7D%7B60%7D)
Substitute 1.5 for BSA and 50 for w
![1.5 = \frac{\sqrt{50*h}}{60}](https://tex.z-dn.net/?f=1.5%20%3D%20%5Cfrac%7B%5Csqrt%7B50%2Ah%7D%7D%7B60%7D)
Multiply both sides by 60
![60*1.5 = \frac{\sqrt{50*h}}{60}*60](https://tex.z-dn.net/?f=60%2A1.5%20%3D%20%5Cfrac%7B%5Csqrt%7B50%2Ah%7D%7D%7B60%7D%2A60)
![60*1.5 = \sqrt{50*h](https://tex.z-dn.net/?f=60%2A1.5%20%3D%20%5Csqrt%7B50%2Ah)
![90 = \sqrt{50*h](https://tex.z-dn.net/?f=90%20%3D%20%5Csqrt%7B50%2Ah)
Square both sides
![90^2 = (\sqrt{50*h})^2](https://tex.z-dn.net/?f=90%5E2%20%3D%20%28%5Csqrt%7B50%2Ah%7D%29%5E2)
![90^2 = 50*h](https://tex.z-dn.net/?f=90%5E2%20%3D%2050%2Ah)
![90^2 = 50h](https://tex.z-dn.net/?f=90%5E2%20%3D%2050h)
![8100 = 50h](https://tex.z-dn.net/?f=8100%20%3D%2050h)
Divide both sides by 50
![\frac{8100}{50} = \frac{50h}{50}](https://tex.z-dn.net/?f=%5Cfrac%7B8100%7D%7B50%7D%20%3D%20%5Cfrac%7B50h%7D%7B50%7D)
![\frac{8100}{50} = h](https://tex.z-dn.net/?f=%5Cfrac%7B8100%7D%7B50%7D%20%3D%20h)
![162 = h](https://tex.z-dn.net/?f=162%20%3D%20h)
![h = 162](https://tex.z-dn.net/?f=h%20%3D%20162)
![h = 162.0\ cm](https://tex.z-dn.net/?f=h%20%3D%20162.0%5C%20cm)
<em>Hence, the patient's height is 162.0cm</em>