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Grace [21]
3 years ago
15

R+6≥11 ; {4,5,6,7} Answer choices: 4, 5, 6,7

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0

For this case we have the following inequality:

r + 6 \geq11

To solve we have:

Subtracting 6 from both sides of the equation:

r \geq11-6\\r \geq5

Thus, the solution is given by all values of r greater than or equal to 5.

Answer:

The solution is given by all values of r greater than or equal to 5.

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PLEASE HELP!! 30 POINTS
AveGali [126]
The answer is b if you add 3 plus -5 that would have given you negative -2
3 0
3 years ago
I don’t really understand this
ankoles [38]

Answer

pretty sure its a or c, sorry I cant be more specific

Step-by-step explanation:

3 0
3 years ago
Pleaseeee help me either no one is answering or they're wrong w no explanation:(
pshichka [43]

Answer:

Felicia, these questions are tough for a lot of reasons, so it makes sense to me that nobody is giving you the right answers.   here is a right one  :)

Step-by-step explanation:

1st we need a strategy.  brainstorm :P   we are given the cost of material for boxes in area,  we are asked how much 12 boxes would cost.  let's find the area of the material for one box multiply that by the given cost. and then multiply that by 12  for the total cost.  seem good?  Yes there are other good ways to solve this problem if you're thinking that.  this is just how I'm arbitrarily choosing to solve it.

1) surface area of prism box

1a) triangles on ends

1/2* b*p  ( I think 6.2 is P for you, not positive about that)

1/2*6.4*6.2= 19.84  

1b) flat sides

6.4*25 =160 ( this is B )

1c) add up the 5 sides

160*3 + 19.84 * 2  = 839.68 cm^{2}

2) find the cost on 1 box

839.68 cm^{2} *  $0.0001 = 0.8397

about $0.84

3) find the cost for 12 boxes

0.8397 * 12 = 10.076

about $10.08

try those answers :)

8 0
3 years ago
Find the equation of the ellipse that has endpoints of the major axis at (-2, 4) and (6, 4) and has endpoints of a minor axis at
expeople1 [14]

Step-by-step explanation:

Use the standard form (x−h)2a2+(y−k)2b2=1 ( x − h ) 2 a 2 + ( y − k ) 2 b 2 = 1 . If the x-coordinates of the given vertices and foci are the same, then the major axis is parallel to the y-axis. Use the standard form (x−h)2b2+(y−k)2a2=1 ( x − h ) 2 b 2 + ( y − k ) 2 a 2 = 1 .

3 0
4 years ago
Sketch and prove the following for the two congruent triangles ∆ABC and ∆DEF.
madreJ [45]

Answer:

See explanation

Step-by-step explanation:

<u>Given:</u> ΔABC ≅ ΔDEF

AM, DN - medians

<u>Prove:</u> AM ≅ DN

Proof:

1. Congruent triangles ABC and DEF have congruent corresponding parts:

  • AB ≅ DE;
  • BC ≅ EF;
  • ∠ABC ≅ ∠DEF.

2. BM ≅ MC - definition of the median AM;

3. EN ≅ NF - definition of the median DN;

4. AB ≅ 2BM, EF ≅ 2EN

BM ≅ 1/2 AB,

EN ≅ 1/2 EF,

thus, BM ≅ EN

5. Consider two triangles ABM and DEN. In these triangles \:

  • AB ≅ DE (see 1));
  • BM ≅ EN (see 4));
  • ∠ABM ≅ ∠DEN (see 1).

So, ΔABM ≅ ΔDEN by SAS postulate.

6. Congruent triangles ABM and DEN have congruent corresponding sides BM and DN.

3 0
3 years ago
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