Given:
Joining fee = $28
Fee of each event = $4
To find:
Total cost for someone to attend 4 events.
Solution:
Let the number of events be x and total fee be y.
Fee for 1 event = $4
Fee for x events = $4x
Joining fee remains constant. So, the total fee is

Substitute x=4 in this equation.



Therefore, total cost of 4 events is $44.
The answer is 6 and 1/15.
Answer:
B
explanation:
I am sorry that I am not sure how to expalin but this is the correct answer.
Answer: The required expected value is $3.46.
Step-by-step explanation:
Since we have given that
Number of value of 4 or less are
2,3,4
So, there are 12 in numbers.
So, probability would be

Since Aces are considered as the highest card in the deck.
So, remaining probability would be

Amount paid or value of 4 or less = $165
Amount not paid for other case = $45
So, the expected value would be

Hence, the required expected value is $3.46.
The answer is 3 pens and 4 pencils. Hope this helps