We know that
x-------------> length rectangle launch tray
w------------< width rectangle launch tray------> 15 cm
<span>length is at least 20% greater than it's width
</span>x>=1.2w---------> x>=1.2*15
the answer part a) is
x>=18 ---------------> (<span> inequality to represent this situation)
part b) </span><span>suppose X is a whole number find the least possible permitted and the least possible area of the lunch tray
</span><span>
the least possible permitted length is 18 cm
</span>the least possible area of the lunch tray is 18*15=270 cm²
Answer:
16c-16
Step-by-step explanation:
11c-8+5c-8
16c -8 -8
16c-16
The last one would be the right one I believe
Answer:
a = 16
b = 10
In the equation from the question there's no value that you can determine for c.
Step-by-step explanation:
- (4x)(3z+y)+2x(3y+2z)=axz+bxy
- 12xz+4xy+6xy+4xz
- 16xz+10xy
