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3 years ago

Graph y 2 = 3/4(x – 6) using the point and slope given in the equation Use the line tool and select two points on the line.

Mathematics

1 answer:

Harman [31]3 years ago

5 0

Answer:

(8,0) and (0,6)

Step-by-step explanation:

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Please help. 10 points. Please do not guess. Guesses will be reported. Thanks

Allushta [10]

The intersecting secant-tangent theorem says that

$AP^2=PT\cdot TO$

where T is the point at which line segment PO touches the circle. Similarly,

$BP^2=PT\cdot TO$

so we have

$AP^2=BP^2\implies AP=BP$

OP is of course as long as itself, and AO and BO are radii of the same circle so they have the same lengths.

This means triangles APO and BPO are congruent, which means angles APO and BPO are congruent, so angle APB is bisected by PO.

8 0

3 years ago

Yes I need help plz !!!!!!!!!!!

Delicious77 [7]

Answer:

Slope = -2

Step-by-step explanation:

slope = (y₂ - y₁)/(x₂ - x₁)

s = (6 - 0)/(-3 - 0)

s = 6 / -3

s = -2

I hope this helped and please mark me as brainliest!

4 0

3 years ago

Read 2 more answers

A bag contains purple marbles and white marbles, 30 in total. The number of purple marbles is 6 less than 5 times the number of

Nastasia [14]

The answer would be 9

7 0

3 years ago

Read 2 more answers

In a survey of adults who follow more than one sport, 30% listed football as their favorite sport. You survey 15 adults who foll

maxonik [38]

Answer: 0.5

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_x\ p^x(q)^{n-x}$ , where P(x) is the probability of getting success in x trials , n is the total trials and p is the probability of getting success in each trial.

Given : The probability that the adults follow more than one game = 0.30

Then , q= 1-p = 1-0.30=0.70

The number of adults surveyed : n= 15

Let X be represents the adults who follow more than one sport.

Then , the probability that fewer than 4 of them will say that football is their favorite sport,

$P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5$

Hence, the probability rounded to the nearest tenth that fewer than 4 of them will say that football is their favorite sport =0.5

4 0

3 years ago

What is the graph of this equation

OverLord2011 [107]

Answer:

Look at attached image

Step-by-step explanation:

8 0

3 years ago