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inna [77]
3 years ago
7

Aulo uses an instrument called a densitometer to check that he has the correct ink colour.

Mathematics
1 answer:
Otrada [13]3 years ago
7 0

Answer:

The range is from 1.62 to 1.98.

Step-by-step explanation:

We have to solve for the percentage of the particular value if the range of the answer should be +/- 10% of the particular value.

The value given is 1.8, we thus want to find 10% of that: 1.8 * 10/100 = 0.18

Then, add this value to the original value of 1.8: 1.8+0.18 = 1.98

Furthermore, subtract .18 from from the original value of 1.8: 1.8-0.18 = 1.62

The range will be between these two numbers, so the range is from 1.62 to 1.98.

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PLEASE DROP A CORRECT ANSWER!!
denpristay [2]

Answer:

C

Step-by-step explanation:

you keep the base the same which is 7 . Then add the exponets (small numbers) then you will get 11. Therefore, you put the base 7 over 11.

5 0
3 years ago
A. Evaluate the polynomial
sdas [7]

Answer:

a) y = x³− 5x² + 6x + 0.55 at x = 1.37.

Use 3-digit arithmetic with chopping. Evaluate the percent relative round-off error.

-1.183%

b. Express y as y = ((x − 5)x + 6)x + 0.55 (this is the same equation). Use again 3-digit arithmetic with chopping. Evaluate the percent relative round-off error and compare with part (a). Make the conclusion about which form of the polynomial is superior.

-0.161%

Comparing part a and b together, part b is more superior because the percent(%) error is smaller when compared to part a

Step-by-step explanation:

a) y = x³− 5x² + 6x + 0.55 at x = 1.37.

Use 3-digit arithmetic with chopping. Evaluate the percent relative round-off error.

Let's evaluate before applying the 3 digit arithmetic chopping rule

y = 1.37³ - 5 × 1.37² + 6 × 1.37 + 0.55

y = 1.956853

Let evaluate each components of the polynomial one by one

Note that: 3-digit arithmetic chopping means to approximate chop off or remove number after the 3 significant figures.

y = x³− 5x² + 6x + 0.55 at x = 1.37.

x³ = 1.37³ = 2.571353

≈ 2.57

x² = 1.37² = 1.8769

≈ 1.88

5x² = 1.87 × 5

= 9.35

x = 1.37

6x = 1.37 × 6

6x = 8.22

Evaluating the polynomial

y = 2.57 - 9.38 + 8.22 + 0.55

y = 1.98

The percent relative round-off error =

1.956853 - 1.98/1.956853 × 100

= -1.183%

b. Express y as y = ((x − 5)x + 6)x + 0.55 (this is the same equation). Use again 3-digit arithmetic with chopping. Evaluate the percent relative round-off error and compare with part (a). Make the conclusion about which form of the polynomial is superior.

y = ((x − 5)x + 6)x + 0.55

Evaluating with the 3 digit chop off rule is applied

= ((1.37 - 5)1.37 + 6)1.37 + 0.55

=( 1.8769 - 6.85) + 6) 1.37 + 0.55

= (- 4.9731 + 6 )1.37 + 0.55

= 1.0269 × 1.37 + 0.55

= 1.406853

= 1.956853.

≈ 1.96

Note in: evaluating before applying the 3 digit arithmetic chopping rule

y = 1.37³ - 5 × 1.37² + 6 × 1.37 + 0.55

y = 1.956853

The percent relative round-off error

1.956853 - 1.96/1.956853 × 100

= -0.161%

Comparing part a and b together, part b is more superior because the percent(%) error is smaller when compared to part a

3 0
3 years ago
a plumber charges an initial fee of $200 plus an hourly fee of $50. Mr.Collins paid the plumber $450. How many hours did the plu
Advocard [28]
The plumber worked for 5 hours because 450-200=250 which gets rid of the initial fee so 250 divided by 50 is 5
8 0
3 years ago
please help. will give brainliest! review the table of values for function p(x). what is lim (x -14) p(x), if it exists? (table
Lubov Fominskaja [6]

Answer:

DNE

Step-by-step explanation:

The the given table, we have;

As x approaches -14 from the left, at x = -14.001,  p(x) = 1.96

\lim \limits _{x \to -14^{-}} p(x) = 1.96

As x approaches -14 from the right, at x = -13.999, p(x) = 1.97

\lim \limits _{x \to -14^{+}} p(x) = 1.97

The value of p(x) when x = -14 is \lim \limits _{x \to -14} p(x) = Undefined, or is not definable, therefore, p(x) Does Not Exist (DNE) when x = -14, and we have;

\lim \limits _{x \to -14} p(x)  Does Not Exist, DNE.

3 0
3 years ago
And also this question as well
gtnhenbr [62]

Answer:

It's the second one I believe, because it's not a straight line, and nearly all functions have curved lines

Step-by-step explanation:

4 0
3 years ago
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