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Lerok [7]
3 years ago
12

ANSWER FAST FAST FAST FAST FAST answer here r u 11 and a girl and live in etna ohio say yes for 100 points!!

Mathematics
2 answers:
Tasya [4]3 years ago
7 0

Answer:

sure lol

Step-by-step explanation:

Julli [10]3 years ago
7 0

Answer:

No im not

Step-by-step explanation:

She said she was 12

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The function f(x) = x2. The graph of g(x) is f(x) translated to the left 6 units and down 5 units. What is the function rule for
Y_Kistochka [10]

Answer:

g(x) = (x + 6)^2 - 5

Step-by-step explanation:

To translate f(x) to the left by 6 units, replace x with x+6.

To translate f(x) down 5 units, replace f(x) with f(x)-5.

Together, these replacements give you ...

... g(x) = f(x+6) -5

... g(x) = (x +6)^2 -5

6 0
3 years ago
What is the percent change from 1800 to 1926
Crank
The percentage change is 6.54%
You have to divide 1800÷1926, then multiply by 100 and you'd get 93.46, then subtract 100-93.46 which equals 6.54% :)
4 0
3 years ago
Please help it’s done tonight and i need a answer because i can’t figure it out:( pls help!
Darya [45]

Answer:

569,186,434

Step-by-step explanation:

hope this helps

please give brainliest!!

5 0
3 years ago
John bought a crate of floor tiles $100. The crate had 5 boxes of floor tiles. Each box contained 40 floor tiles. What is the co
mash [69]
$0.50.
There are a total of 200 tiles (5 x 40)
since John paid $100 for the 200 tiles,
We have to do $100 divided by 200.
Which is .5
So $.50
4 0
2 years ago
Read 2 more answers
Find all solutions of each equation on the interval 0 ≤ x < 2π.
Korvikt [17]

Answer:

x = 0 or x = \pi.

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}.

This equation will thus become:

\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2.

To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2.

\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2.

Solve this equation for u:

\displaystyle \frac{u^{2} + 1}{u^{2}} = 2.

u^{2} + 1 = 2 u^{2}.

u^{2} = 1.

Given that 0 \le u \le 1, u = 1 is the only possible solution.

\cos^{2}{x} = 1,

x = k \pi, where k\in \mathbb{Z} (i.e., k is an integer.)

Given that 0 \le x < 2\pi,

0 \le k.

k = 0 or k = 1. Accordingly,

x = 0 or x = \pi.

8 0
3 years ago
Read 2 more answers
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