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3 years ago

How do you write a sentence about comparing the values of the nines in the number 199,204

Mathematics

1 answer:

Margarita [4]3 years ago

8 0

Answer:

Step-by-step explanation:

The first 9 stands for 90,000 and the second for 9 000 so the first 9 is worth

90,000 / 9,000 equals 10 times the second one.

You might be interested in

Express 112 as a product of prime numbers in index form?

alexgriva [62]

112
/ \
2 56
/ \
2 28
/ \
2 14
/ \
2 7

So, the answer is 2 x 2 x 2 x 7 or 2^3 x 7

6 0

3 years ago

25 is what percent less than 35

mars1129 [50]

Difference between 25 and 35 = 35 -25
   = 10
Then
percentage by which 25 is less than 35 =(10/35) * 100
   = (2/7) * 100
   = 200/7
   = 28.57 percent
So 25 is 28.57% less than 35.This is the only clear way of solving these kind of problems. I hope you have understood the method used to solve this problem. Hopefully you can do such type of problems without needing any help.

8 0

3 years ago

Read 2 more answers

What is -3 the sum of 5

Ainat [17]

The solution is 2. -3+5=2

6 0

4 years ago

ASAP HELP PLEASE! WILL GIVE BRAINLIEST

Mila [183]

Answer:

Least Value = 2
Median = 6
Greatest Value = 10
Third Quartile = 8
Range = 8 (10 - 2 = 8)
First Quartile = 5

Step-by-step explanation:

7 0

3 years ago

Set up the integral that represents the arc length of the curve f(x) = ln(x) + 5 on [1, 3], and then use Simpson's Rule with n =

marta [7]

Answer:

The integral for the arc of length is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

By using Simpon’s rule we get: 1.5355453

And using technology we get: 2.3020

The approximation is about 33% smaller than the exact result.

Explanation:

The formula for the length of arc of the function f(x) in the interval [a,b] is:

$\displaystyle\int_a^b \sqrt{1+[f'(x)]^2}dx$

We need the derivative of the function:

$f'(x)=\frac{1}{x}$

And we need it squared:

$[f'(x)]^2=\frac{1}{x^2}$

Then the integral is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

Now, the Simposn’s rule with n=4 is:

$\displaystyle\int_a^b g(x)}dx\approx\frac{\Delta x}{3}\left( g(a)+4g(a+\Delta x)+2g(a+2\Delta x) +4g(a+3\Delta x)+g(b) \right)$

In this problem:

$a=1,b=3,n=4, \displaystyle\Delta x=\frac{b-a}{n}=\frac{2}{4}=\frac{1}{2},g(x)= \sqrt{1+\frac{1}{x^2}}$

So, the Simposn’s rule formula becomes:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\\\approx \frac{\frac{1}{3}}{3}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{1}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(1+\frac{2}{2}\right)^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{3}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$

Then simplifying a bit:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx \approx \frac{1}{9}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(\frac{3}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(2\right)^2}} +4\sqrt{1+\frac{1}{\left(\frac{5}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$

Then we just do those computations and we finally get the approximation via Simposn's rule:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\approx 1.5355453$

While when we do the integral by using technology we get: 2.3020.

The approximation with Simpon’s rule is close but about 33% smaller:

$\displaystyle\frac{2.3020-1.5355453}{2.3020}\cdot100\%\approx 33\%$

8 0

3 years ago