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The probability of drawing the first pink ball is .
Because you drew that first pink ball, there are two pink balls left and the total number of balls left is nine.
Hence, the probability of drawing another pink ball after drawing the first pink ball would be:
Let x be the random variable representing defective phone. Let n be the sample size. Let p be the probability that phone is defective.
Given: n=500, p= 0.02
From given information we know that x is random variable such that p is the probability of success and it is constant for each trial. Sample size n is fixed.
X follows Binomial distribution with parameters n=500 and p=0.02
a). The average number of defective phone
E(x) = n*p = 500 * 0.02 = 10
The average number of defective phones is 10.
b)Probability of getting 5 defective phones.
P(X=5) =
=
= 0.037
The probability of getting exactly 5 defective is 0.037.