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Gennadij [26K]
3 years ago
13

Please someone solve for X, I don’t think it needs rounding but I couldn’t come up with an answer.

Mathematics
1 answer:
agasfer [191]3 years ago
5 0

Answer:

x= 10 In (17)

Step-by-step explanation:

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Solve for x for #5 and 6
Alex777 [14]

Answer:

In 5:

UM and MS are equal since the diagonals US and VT have perpendicularly bisected each other.

So,15=6x-3

15+3=6x

18=6x

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ET=TC

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7 0
3 years ago
the sum of two numbers is 63. one ninth of the first number plus one sixth of the second number is 21. find the numbers
PSYCHO15rus [73]

Answer: x= -189, y =252

Step-by-step explanation:

Let the first number be x and second number be y

so

x + y = 63

x = 63-y

now

1/9 of x + 1/6 of y = 21

x/9 + y/6 = 21

substituting x's value from equation i

(63-y)/9 + y/6 = 21

(378-6y+9y)/54 = 21

378+3y = 1134

3y = 1134-378

so, 3y = 756

so, y = 756/3

so, y = 252

now

x = 63-252

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6 0
3 years ago
Liam is saving up for a new cell phone. He uses the equation P= I + HB, where P is the cost
Stels [109]

Answer:

H=\dfrac{P-I}{B}

Step-by-step explanation:

Given the expression: P= I + HB

Where:

  • P = cost  of the phone Liam is saving for.
  • I = amount of money he started with.
  • H = number of hours he  babysits
  • B = hourly rate for babysitting.

We want to find an expression for H, the number  of hours Liam will need to babysit to save enough money for a cell phone.

Our goal is to isolate the variable H in the expression P= I + HB.

P= I + HB

Subtract I from both sides

P-I=I-I+HB

HB=P-I

Divide both sides by B

\dfrac{HB}{B} =\dfrac{P-I}{B}\\\\$Therefore\\\\H=\dfrac{P-I}{B}

4 0
3 years ago
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