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3 years ago

What is the value of log E 100

Mathematics

2 answers:

Ivan3 years ago

7 0

Answer:

4.605170185988091

Step-by-step explanation:

ln 100 = 4.605170185988091

e^4.605170185988091 = 100

Marina86 [1]3 years ago

3 0

Step-by-step explanation:

100=1 log 10(1)=0

I hope this is helpful for you

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A bakery offers a sale price of $3.50 for 4 muffins. What is the price per dozen?

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$10.50 per dozen muffins

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A line with a slope of – 5 passes through the points (3,n) and (4, – 5). What is the value of n?

masha68 [24]

Answer:

n = 0

Step-by-step explanation:

slope = y2-y1/x2-x1

-5 -n / 4-3 = -5

-5 -n /1 =-5

-5 - n = -5

n = 0

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In Pant Science (May 2010), a group of Japanese environmental scientists investigated the ability of a hybrid tomato plant to pr

Neporo4naja [7]

Answer:

a) P(x > 120) = 0.03288

b) P(100 < x < 110) = 0.46777

c) value of a for which P(x < a) = 0.25

a = 99.91

Step-by-step explanation:

This is a normal distribution problem with

Mean = μ = 105.3

Standard deviation = σ = 8.0

a) P(x > 120)

To work this, we first need To convert 120 go standardized/normalized/z-scores.

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (120 - 105.3)/8.0 = 1.84

To determine P(x > 120) = P(z > 1.84)

We use the tables for these probabilities now.

P(x > 120) = P(z > 1.84) = 1 - P(z ≤ 1.84) = 1 - 0.96712 = 0.03288

b) P(100 < x < 110)

We normalize the two value in the inequality

For 100,

z = (x - μ)/σ = (100 - 105.3)/8.0 = -0.66

For 110,

z = (x - μ)/σ = (110 - 105.3)/8.0 = 0.59

To determine P(100 < x < 110) = P(-0.66 < z < 0.59)

We use the tables for these probabilities now.

P(100 < x < 110) = P(-0.66 < z < 0.59) = P(z < 0.59) - P(z < -0.66) = 0.72240 - 0.25463 = 0.46777

c) value of a for which P(x < a) = .25

Let the z-score of a be z'

z' = (x - μ)/σ = (a - 105.3)/8.0

P(x < a) = P(z < z') = 0.25

Using the table, z' = - 0.674

-0.674 = (a - 105.3)/8

a - 105.3 = -5.392

a = 105.3 - 5.392 = 99.91

Hope this Helps!!!

5 0

3 years ago

A population has the following characteristics.(a) A total of 25% of the population survives the first year. Of that 25%, 75% su

zaharov [31]

Answer:

After 1st year, the age distribution will be

$x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

After 2nd year, the age distribution will be

$x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]$

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

$A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right]$

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

$x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right]$

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

$x_1 = A \cdot x$

$x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right]$

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

$x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

After 2nd year, the age distribution will be

$x_2 = A \cdot x_1$

$x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

$x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]$

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4 years ago

Jack bought a 16 pound bag of dog food his dog ate 2/3 of the food and a month how many pounds of food did the dog eat in a mont

LuckyWell [14K]

10.6666666667 lbs. is the answer

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3 years ago

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