When you rotate across the x-axis it will be in quadrant 4 now and then when rotating a point 180 degrees counterclockwise about the origin our point A(x,y) becomes A'(-x,-y). So all you do is make both x and y negative.
hope this helps:))
Sorry if you cant see it but anyway the answer is 51.6 i put the decimal in the wrong place at first then i realized that i had to carry over the decimal 2 times
Answer: The shaded area is 99.55 units squared.
Step-by-step explanation:
r = 3.2
Now, we can see that the sides of the square are equal to two times the diameter of the circles (or four times the radius of the circles), so the length of the sides of the square is:
L = 2*(2*3.2) = 12.8
The area of the square is A1 = L^2 = 12.8*12.8 = 163.84 units squared.
the shaded semicircle has a diameter of 4 times r (so the radius is 2 times r), and the area is equal to half the area of a circle:
A2 = (1/2)*pi*(2r)^2 = (1/2)*3.14*(6.4)^2 = 64.31 units squared.
And now we must subtract the area of the four smaller circles inside the square, the area of each one is:
A3 = pi*r^2 = 3.14*(3.2)^2 = 32.15 units squared.
Then the shaded area is:
A = A1 + A2 - 4*A3 = 163.84 + 64.31 - 4* 32.15 = 99.55 units squared.
