**Answer:**

3/5 because you find what goes into each and simplify. 9/15 each divided by 3. 9/3=3 15/3=5 so 3/5 is your answer.

C HOPE IT HELPSS hdhdhehehsuieksjsjajajanasbdbhsYQYYAYYA

**Answer:**

2x² + 7x - 4

**Step-by-step explanation:**

(2x-1)(x+4)

= (2x)(x) + (2x)(4) + (-1)(x) + (-1)(4)

=2x² + 8x - x -4

=2x² + 7x - 4

<span>Harold worked 27 hours at a rate of $13.25 per hour.

27 * $13.25 = $357.75 so line 2 is the answer.

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**Answer:**

(First of all its 20 points not 40 but any ways) A ferris wheel has a raidus of 20 m. Passengers get on halfway up on the right side. The direction of rotation is counter clockwise. The bottom of the ferris wheel is 2 m above ground. It rotates every 36 seconds. Determine height above the ground after 15 seconds algebraically. Determine seconds to the nearest tenth when height is 38 m above the ground algebraically.

**

let t=seconds after wheel starts to rotate.

let h=meters above ground after wheel starts to rotate

..

The formula I got: h(t)=20sin(πt/18)+22

This is close to the formula you got, except I left the negative sign out since passengers start to rise after the wheel starts going counter-clockwise.

..

After 15 seconds:

h=20sin(15π/18)+22

=20sin(5π/6)+22

=20*(1/2)+22

=32 m

..

When h=38 m

38=20sin(πt/18)+22

38-22=20sin(πt/18)

20sin(πt/18)=16

sin(πt/18)=16/20=4/5=.8

arcsin(.8)=0.927

πt/18=0.927 (radians)

t=(.927*18)/π≈5.31

..

height above the ground after 15 seconds≈38 m

seconds elapsed when height is 38 m above ground≈**5.3 seconds**