Answer:
3/5 because you find what goes into each and simplify. 9/15 each divided by 3. 9/3=3 15/3=5 so 3/5 is your answer.
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Answer:
2x² + 7x - 4
Step-by-step explanation:
(2x-1)(x+4)
= (2x)(x) + (2x)(4) + (-1)(x) + (-1)(4)
=2x² + 8x - x -4
=2x² + 7x - 4
<span>Harold worked 27 hours at a rate of $13.25 per hour.
27 * $13.25 = $357.75 so line 2 is the answer.
</span>
Answer:
(First of all its 20 points not 40 but any ways) A ferris wheel has a raidus of 20 m. Passengers get on halfway up on the right side. The direction of rotation is counter clockwise. The bottom of the ferris wheel is 2 m above ground. It rotates every 36 seconds. Determine height above the ground after 15 seconds algebraically. Determine seconds to the nearest tenth when height is 38 m above the ground algebraically.
**
let t=seconds after wheel starts to rotate.
let h=meters above ground after wheel starts to rotate
..
The formula I got: h(t)=20sin(πt/18)+22
This is close to the formula you got, except I left the negative sign out since passengers start to rise after the wheel starts going counter-clockwise.
..
After 15 seconds:
h=20sin(15π/18)+22
=20sin(5π/6)+22
=20*(1/2)+22
=32 m
..
When h=38 m
38=20sin(πt/18)+22
38-22=20sin(πt/18)
20sin(πt/18)=16
sin(πt/18)=16/20=4/5=.8
arcsin(.8)=0.927
πt/18=0.927 (radians)
t=(.927*18)/π≈5.31
..
height above the ground after 15 seconds≈38 m
seconds elapsed when height is 38 m above ground≈5.3 seconds
