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3 years ago

Fill in the boxes to make a true statement. (_-3i)-(15+_i)=7-12i

Mathematics

1 answer:

brilliants [131]3 years ago

5 0

Answer:

blank space= $\frac{31}{2}$ + $\frac{13i}{2}$

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-3x + 3y =3 -5x + y =13 Solve as a whole number

anzhelika [568]

Answer:

X = 3 x − 14

y = − x + 5

Step-by-step explanation:

Solve for the first variable, then substitute the result into the other equation.

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2 years ago

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At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not

Nikitich [7]

If $f(x, y, z) = c$ represent a family of surfaces for different values of the constant $c$ . The gradient of the function $f$ defined as $\nabla f$ is a vector normal to the surface $f(x, y, z) = c$ .

Given the paraboloid

$y = x^2 + z^2$ .

We can rewrite it as a scalar value function f as follows:

$f(x,y,z)=x^2-y+z^2=0$

The normal to the paraboloid at any point is given by:

$\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\ \\ =2xi-j+2zk$

Also, the normal to the given plane $3x + 2y + 7z = 2$ is given by:

$3i+2j+7k$

Equating the two normal vectors, we have:

$2x=3\Rightarrow x= \frac{3}{2} \\ \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}$

Since, -1 = 2 is not possible, therefore there exist no such point on the paraboloid $y = x^2 + z^2$ such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2.

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4 years ago

Samantha's dog weighs 14.25 pounds. Eric's dog weighs 43.5 pounds. What is the difference between the two dogs weight?

dmitriy555 [2]

Answer:

29.25

Step-by-step explanation:

Brainliest?

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3 years ago

All rational numbers are integers trure or false

slega [8]

True.

The rational numbers include all the integers, plus all fractions, or terminating decimals and repeating decimals. ... All natural numbers, whole numbers, and integers are rationals, but not all rational numbers are natural numbers, whole numbers, or integers.

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3 years ago

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∠A and \angle B∠B are supplementary angles. If m\angle A=(2x+26)^{\circ}∠A=(2x+26)

ValentinkaMS [17]

we know angles A and B are supplementary, thus their sum is 180°.

$\stackrel{\measuredangle A}{(2x+26)}~~ + ~~\stackrel{\measuredangle B}{(x+25)}~~ = ~~180\implies 3x+51=180\implies 3x=129\\\\\\x=\cfrac{129}{3}\implies x=43~\hspace{10em}\stackrel{\measuredangle B = 43 + 25}{68}$

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3 years ago