All categories

2 years ago

A salesperson is paid an 8.25% commission on sales when the invoice is

Mathematics

1 answer:

son4ous [18]2 years ago

7 0

Answer:

<em>The salesperson's commission for this month is $3,803</em>

Step-by-step explanation:

<u>Percentages</u>

Let's call x to the sales volume, not including commission.

The salesperson is paid an 8.25% commission on sales, thus the total invoice is x + 8.25%x = x + 0.0825x = 1.0825x

We are given this total invoice, thus:

1.0825x = $49,900

Dividing by 1.0825:

x = $46,097

The salesperson's commission is

0.0825*$46,097=$3,803

The salesperson's commission for this month is $3,803

You might be interested in

You already know its another giveaway

nasty-shy [4]

Answer: yay thxs

Step-by-step explanation:

5 0

2 years ago

No Bots pls and ill give brainly when two people answer

otez555 [7]

Depending on your graph go down 4 an across until u get to the other dot

3 0

3 years ago

Read 2 more answers

Cassie has test grades of 71, 78 and 83 on the first three tests in her

Neporo4naja [7]

Answer:

x ≥ 88

Step-by-step explanation:

In order to have at least an average of 80 after 4 tests, the sum of her scores must be at least 80 * 4 = 320 so we can write the following inequality:

71 + 78 + 83 + x ≥ 320

232 + x ≥ 320

x ≥ 88

3 0

2 years ago

Read 2 more answers

I roll a fair die twice and obtain two numbers X1= result of the first roll and X2= result of the second roll. Given that I know

azamat

By definition of conditional probability,

$P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{P((X_1=4\text{ or }X_2=4)\text{ and }X_1+X_2=7)}{P(X_1+X_2=7)}$

$=\dfrac{P((X_1=4\text{ and }X_1+X_2=7)\text{ or }(X_2=4\text{ and }X_1+X_2=7))}{P(X_1+X_2=7)}$

Assuming a standard 6-sided fair die,

if $X_1=4$ , then $X_1+X_2=7$ means $X_2=3$ ; otherwise,
if $X_2=4$ , then $X_1=3$ .

Both outcomes are mutually exclusive with probability $\frac1{36}$ each, hence total probability $\frac2{36}=\frac1{18}$ .

Of the 36 possible outcomes, there are 6 ways to sum the integers 1-6 to get 7:

(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

and so a sum of 7 occurs $\frac6{36}=\frac16$ of the time.

Then the probability we want is

$P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{\frac1{18}}{\frac16}=\frac13$

6 0

3 years ago

Is (1, 1) a solution to this system of equations? 4x + 6y - 10 x + 13y = 11 yes no Submit

fredd [130]

Answer:

Explanation:

Given 4x + 6y - 10x + 13y = 11

If (1, 1) is a solution, then substituting x = 1 and y = 1 into the left hand side of the equation gives 11.

Doing this, we have:

4(1) + 6(1) - 10(1) + 13(1)

= 4 + 6 - 10 + 13

= 13

4 0

10 months ago