करताह! गर्मियों में घड़े का जल ठंडा क्यों होता है?

B) How does electron gain enthalpy change along a period and in a group?

chubhunter [2.5K]

Answer:

Electron gain enthalpy becomes more and more negative from left to right in a period. As we move across a period from left to right the atomic size decreases and the nuclear charge increases

3 0

3 years ago

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Define Chemical Properties ?

Anastaziya [24]

Explanation:

<h3>A chemical property is a characteristic of a particular substance that can be observed in a chemical reaction</h3>

. Some major chemical properties include flammability, toxicity, heat of combustion, pH value, rate of radioactive decay, and chemical stability.

3 0

3 years ago

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Apply scientific knowledge and understanding to determine how many grams of carbon dioxide are produced from the combustion of 2

lidiya [134]

Answer:

749 grams CO₂

Explanation:

To find the amount of carbon dioxide produced, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass from periodic table), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio via reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The desired unit should be in the numerator. The final answer should have 3 significant figures because the given value (250. grams) has 3 sig figs.

Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.008 g/mol)

Molar Mass (C₃H₈): 44.094 g/mol

1 C₃H₈ + 5 O₂ ---> 3 CO₂ + 4 H₂O

Molar Mass (CO₂): 12.01 g/mol + 2(16.00 g/mol)

Molar Mass (CO₂): 44.01 g/mol

250. g C₃H₈ 1 mole C₃H₈ 3 moles CO₂ 44.01 g
------------------ x ---------------------- x ---------------------- x -------------------- =
44.094 g 1 mole C₃H₈ 1 mole CO₂

= 749 grams CO₂

6 0

2 years ago

Calculate the amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C.

qwelly [4]

Answer:

The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

Between heat and temperature there is a direct proportional relationship. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

c= 4.184 $\frac{J}{g*C}$
m= 32 g
ΔT= Tfinal - Tinitial= 22°C - 8°C= 14°C

Replacing:

Q= 32 g* 4.184 $\frac{J}{g*C}$ *14 °C

Solving:

Q= 1,874.432 J

The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J

7 0

3 years ago

Two billiard balls having masses of 0.2 kg and 0.15kg approach each other. The first ball having a velocity of 2m/s hit the seco

Gekata [30.6K]

Answer: The velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.

Explanation:

Given: $m_{1}$ = 0.2 kg, $m_{2}$ = 0.15 kg

$v_{1}$ = 2 m/s, $v_{2}$ = 0 m/s, $v'_{1}$ = ?, $v'_{2}$ = 1.5 m/s

Formula used is as follows.

$m_{1}v_{1} + m_{2}v_{2} = m_{1}v'_{1} + m_{2}v'_{2}$

where,

v = velocity before collision

v' = velocity after collision

Substitute the values into above formula as follows.

$m_{1}v_{1} + m_{2}v_{2} = m_{1}v'_{1} + m_{2}v'_{2}\\0.2 kg \times 2 m/s + 0.15 kg \times 0 m/s = 0.2 kg \times v'_{1} + 0.15 kg \times 1.5 m/s\\0.4 kg m/s + 0 = 0.2v'_{1} + 0.225 kg m/s\\0.2v'_{1} kg = 0.175 kg m/s\\v'_{1} = \frac{0.175 kg m/s}{0.2 kg}\\= 0.875 m/s$

Thus, we can conclude that the velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.

4 0

3 years ago

करताह!गर्मियों में घड़े का जल ठंडा क्यों होता है?​

करताह!गर्मियों में घड़े का जल ठंडा क्यों होता है?