A sample of a compound contains 60.0 g C and 5.05 g H.
divide by molar mass of C(12) and H(1) to get molar ratio
C: 60/12=5 and H: 5/1=5
so C:H=5:5=1:1
total molar mass=78
divide by 1C+1H to find the formula: 78/(12+1)=78/13=6
compound is C6H6
Line 1: straight horizontal line
Line 2: straight line at a slope
Line 3: exponential growth curve
Line 4: the topmost curve (the one that initially increases but then starts levels out)
Answer:
B
Explanation:
I hope it helps you good luck
Answer:
See explanation
Explanation:
A net ionic equation shows only the chemical species that are involved in a reaction, while a complete ionic equation also includes the spectator ions(Khan Academy).
From the species shown in the image we can write the molecular equation, ionic equation and net ionic equation and also identify the spectator ions.
Chemical equation: KX + BY --------> BX + AY
Ionic Equation; X^- + A^+ + B^+ + Y^- -----> BX + A^+ + Y^-
Spectator ions; A^+ and Y^-
Net Ionic Equation; X^- + B^+ ------> BX
From the given observations,
You can see that as the concentration is doubled, half-life is halved.
That is,half-life is inversely proportional to concentration
As t( half-life) ~ 1/a^(n-1)
For this case n = 2,second order reaction.
R = k X a^n
Using the above formula you will get the rate and rate constant.
