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Contact [7]
3 years ago
15

Between which two consecutive integers does negative square root of 75 lie between?

Mathematics
1 answer:
Marina86 [1]3 years ago
3 0

Answer:

sqrt (75) lies between 8 and 9 and is closer to 9

Step-by-step explanation:

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Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
Please help
oksian1 [2.3K]

Answer:

1: 11√3 - 7√6

2: 11√3 - 7√6

3: -9

4:12

Step-by-step explanation:

To add radicals they need to have the same radical part for the first one we have

7√3- 4√6 + √48 - √54

We can simplify the last two into 4√3 and 3√6

So we have 7√3 - 4√6 + 4√3 - 3√6

adding similar radicals we get

11√3 - 7√6

For the second one we have 11√3 - 7√6

There's nothing we can do from here so keep that as your answer

This one is quite easy -3√9

square root of 9 is 3

so we have -3*3 which is -9

next is

4√9

same deal as the one before

3*4=12

5 0
3 years ago
Read 2 more answers
Write a word problem that can be described by the division expression 3÷1/4. Use complete sentences in your answer
AURORKA [14]
The question is simply asking us to create a word problem.
The word problem describing the division expression  3÷1/4 will be:
Given that Annie has 3 oranges and he wants to each orange into quarters, how many quarters will Annie have in total?
 
4 0
3 years ago
Read 2 more answers
Find A and B. Using the image above.
NeX [460]

Answer:

a = 7, b = \frac{7\sqrt{3} }{3}

Step-by-step explanation:

Using the sine ratio in the left right triangle and the exact value

sin45° = \frac{1}{\sqrt{2} } , then

sin45° = \frac{opposite}{hypotenuse} = \frac{a}{7\sqrt{2} } = \frac{1}{\sqrt{2} } ( cross- multiply )

a × \sqrt{2} = 7\sqrt{2} ( divide both sides by \sqrt{2} )

a = 7

--------------------------------------------------------

Using the tangent ratio in the right triangle on the right and the exact value

tan60° = \sqrt{3} , then

tan60° = \frac{opposite}{adjacent} = \frac{a}{b} = \frac{7}{b} = \sqrt{3} ( multiply both sides by b )

b × \sqrt{3} = 7 ( divide both sides by \sqrt{3} )

b = \frac{7}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = \frac{7\sqrt{3} }{3}

7 0
3 years ago
Its pretty easy if you are good at math! Please help!
aleksley [76]

Step-by-step explanation:

Explanation:

The trick is to know about the basic idea of sequences and series and also knowing how i cycles.

The powers of i will result in either: i, −1, −i, or 1.

We can regroup i+i2+i3+⋯+i258+i259 into these categories.

We know that i=i5=i9 and so on. The same goes for the other powers of i.

So:

i+i2+i3+⋯+i258+i259

=(i+i5+⋯+i257)+(i2+i6+⋯+i258)+(i3+i7+⋯+i259)+(i4+i8+⋯+i256)

We know that within each of these groups, every term is the same, so we are just counting how much of these are repeating.

=65(i)+65(i2)+65(i3)+64(i4)

From here on out, it's pretty simple. You just evaluate the expression:

=65(i)+65(−1)+65(−i)+64(1)

=65i−65−65i+64

=−65+64

=−1

So,

i+i2+i3+⋯+i258+i259=-1

8 0
3 years ago
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