What times what equals 120

Mathematics

2 answers:

Dahasolnce [82]3 years ago

5 0

60x2
120x1
40x3
30x4
24x5

mixer [17]3 years ago

5 0

1x120

2x60

3x40

5x24

6x20

8x15

10x12

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Solve for x Write both solutions, seperated by a comma 4x^2+5x+1=0

stiv31 [10]

Answer:

-1/4 , -1

Step-by-step explanation:

I solved it using Factorization method and Quadratic Equation .

Factorization Method

$4x^2+5x+1=0\\Write +5x- as- a -difference(write+5x-using- two- numbers -in-which-their-sum-is ; 5-and-their-product-is ; 4)\\4x^{2} +4x+1x+1=0\\Factorize-out-common-terms\\4x(x+1)+1(x+1)=0\\Factor-out-(x+1)\\(4x+1)(x+1)=0\\4x+1 =0 \\x+1=0\\4x=0-1\\x =0-1\\4x =-1\\x =-1\\4x=-\frac{1}{4} \\\\Answer = -1/4 , -1$

Quadratic Equation

$4x^2+5x+1=0\\a = 4\\b =5\\c = 1\\\\x =\frac{-b\±\sqrt{b^2 -4ac} }{2a} \\\\x = \frac{-(5)\±\sqrt{(5)^2-4(4)(1)} }{2(4)} \\\\x = \frac{-5\±\sqrt{25-16} }{8} \\\\x = \frac{-5\±\sqrt{9} }{8} \\\\x = \frac{-5\±3}{8} \\\\x =\frac{-5+3}{8} \\\\x = \frac{-5-3}{8} \\\\x = \frac{-2}{8} \\\\x = \frac{-8}{8} \\\\x = -\frac{1}{4} \\x=-1$

5 0

3 years ago

Jasmine's credit card has a $2,000 balance that she carried over from last month. assuming her credit card charges an 18 percent

NikAS [45]

Using simple interest, it is found that her interest charge this month will be of $30.

<h3>Simple Interest</h3>

Simple interest is used when there is a single compounding per time period.

The amount of interest after t years in is modeled by:

I(t) = Prt

In which:

P is the initial amount.

r is the interest rate, as a decimal.

In this problem, considering the time in years, the parameters are:

$P = 2000, r = 0.18, t = \frac{1}{12}$

Hence:

$I(t) = 2000 \times 0.18 \times \frac{1}{12} = 30$

Her interest charge this month will be of $30.

More can be learned about simple interest at brainly.com/question/25296782

4 0

3 years ago

The? half-life of a radioactive substance is 20 years. If you start with some amount of this? substance, what fraction will rema

yarga [219]

$\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\\ t=\textit{elapsed time}\dotfill &120\\ h=\textit{half-life}\dotfill &20 \end{cases} \\\\\\ A=P\left( \frac{1}{2} \right)^{\frac{120}{20}}\implies A=P\left( \frac{1}{2} \right)^6\implies A=P\left( \cfrac{1^6}{2^6} \right)\implies A=\cfrac{1}{64}P$