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sesenic [268]
3 years ago
5

La suma de las edades de Agustín y Pedro es igual a 36,si Agustín tiene 2 años menos que pedro ¿Cuantos años tienen estos chicos

?
Mathematics
1 answer:
Dvinal [7]3 years ago
3 0
No hablo espanol. Hablas ingles?
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Multiply.<br> (5v+6w-7)(-3)<br> Simplify your answer.
Zielflug [23.3K]

Answer:

if my calculator is not wrong Is 21

3 0
2 years ago
What is ​ BC ​ ?<br><br><br> Enter your answer in the box.<br><br> BC=<br> units
kumpel [21]

<u>Answer:</u>

  • The length of BC is 25 units.

<u>Step-by-step explanation:</u>

<u>We know that the triangle is an isosceles triangle. Hence, we know that AB = AC. Let's first solve for x.</u>

  • => 4x + 1 = 2x + 23
  • => 4x - 2x = -1 + 23
  • => 2x = 22
  • => <u>x = 11</u>

<u>Now, let's substitute the value into the expression.</u>

  • => 3x - 8
  • => 3(11) - 8
  • => 33 - 8
  • => <u>25</u>

<u>Hence,</u><u> the length of BC is 25 units.</u>

Hoped this helped.

BrainiacUser1357

5 0
2 years ago
(5k − 1 + 2k3) − (6k3 − 3k2 − 8) + (8k3 − 2k2 − 7k)
Vera_Pavlovna [14]

Answer:

4k^3 + k^2 - 2k + 7

Step-by-step explanation:

Hope this helps, and good luck

3 0
3 years ago
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What is the value of x? Enter your answer in the box. x =
Yuliya22 [10]
What is the equasion then i can tell u the answer
8 0
3 years ago
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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
2 years ago
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