The correct answer is d.We have the following system of linear equations:
(I)

(II)

Let's use the elimination method, then let's multiply the equation (1)

and subtracting (I) and (II):
(I)

∴

(I)

(II)

____________________
(III)

∴

We can find the value of x by substituting y either in (I) or (II). Thus, from (I):

∴

∴

∴

∴

Let's substitute the values of x and y into (I) and (2)
(I)

(II)

Finally the answer is:
Answer: 3*2=6
Step-by-step explanation: Turn the 2 into a 3 then see if it make sense
Answer:
117
Step-by-step explanation:
Let d represent the number of stamps Derek had at first. After he gave 1/9 of his stamps to Ahmad, Ahmad had (d -104) +(d/9). Derek had 4 times this number after giving away d/9 stamps:
(d -d/9) = 4((d -104) +d/9)
(8/9)d = 4d -416 +(4/9)d
416 = (32/9)d . . . . add 416 -8/9d
117 = d . . . . . . . . . . multiply by 9/32
Derek had 117 stamps at first.
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<em>Check</em>
1/9 of Derek's collection is 13 stamps. 104 less than Derek's collection is 13 stamps.
So, Ahmad started with 13 stamps and was given 13 stamps by Derek. Meanwhile, Derek started with 117 stamps and gave away 13, so ended with 104 stamps. That number (104) is 4 times Ahmad's new number (26), as it should be.
This does not need the quadratic formula since there are no variables to begin with:
62-46+4 = 0
20 = 0.
And 20 does not equal 0 so both sides aren't equal.
Soooo not much to do with this question.