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3 years ago

A subway car 34 feet long; 1 inch = 5 feet

Mathematics

1 answer:

ZanzabumX [31]3 years ago

8 0

Answer:

6.8 inches

Step-by-step explanation:

inch= 1 x

feet= 5 34

1×34÷5

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What is the interquartile range if the data set? 5,911,13,16,16,19,21

max2010maxim [7]

Answer:

Step-by-step explanation:

5,9,11,(13,16),16,19,21

the mean(middle number) = (13 + 16) / 2 = 29/2 = 14.5

Q1 = (9 + 11) / 2 = 20/2 = 10

Q3 = (16 + 19) / 2 = 35/2 = 17.5

interquartile range (IQR) = Q3 - Q1 = 17.5 - 10 = 7.5 <==

7 0

3 years ago

At a local store, Kelly and Martin bought some notebooks and pencils. Kelly bought 4 notebooks and 25 pencils for 16.71. Martin

grandymaker [24]

Answer:

9.17

Step-by-step explanation:

6 0

3 years ago

Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random

Katen [24]

Answer:

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

Step-by-step explanation:

Given

$n = 200$

$x_1 = 34$ -- City C

$x_2 = 54$ --- City K

Required

Determine the 90% confidence interval

This is calculated using:

$CI = \bar x \± z\frac{\sigma}{\sqrt n}$

Calculating $\bar x$

$\bar x = \bar x_1 - \bar x_2$

$\bar x = \frac{x_1}{n} - \frac{x_2}{n}$

$\bar x = \frac{34}{200} - \frac{54}{200}$

$\bar x = 0.17 - 0.27$

For a 90% confidence level, the z-score is 1.65. So:

$z = 1.65$

Calculating the standard deviation $\sigma$

$\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }$

So:

$\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }$

$\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}$

So:

$CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}$

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

7 0

3 years ago

Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?

erik [133]

Let

A-----> $\frac{7}{8}$

B-----> $\frac{11}{10}$

C-----> $1$

we know that

Point A-------> Multiply numerator and denominator by $10$

$\frac{7*10}{8*10} =\frac{70}{80}$

Point B-------> Multiply numerator and denominator by $8$

$\frac{11*8}{10*8} =\frac{88}{80}$

Point C-------> Multiply numerator and denominator by $80$

$\frac{1*80}{1*80} =\frac{80}{80}$

Find the distance Point A to Point C

$\frac{80}{80} -\frac{70}{80} =\frac{10}{80}$

Find the distance Point B to Point C

$\frac{88}{80} -\frac{80}{80} =\frac{8}{80}$

therefore

$\frac{8}{80} < \frac{10}{80}$

Point B is closer to Point C

$\frac{11}{10}$ is closer to $1$

the answer is

$\frac{11}{10}$ is closer to $1$

5 0

3 years ago

Read 2 more answers

Determine the measure of the angle labeled (4x+7)°.

Murrr4er [49]

Answer:

Step-by-step explanation:

First, combine like terms

4x+7=6x-9

+9 +9

4x+16=-9

-16 -16

Then divide by four to isolate x

4x=-25

x=-6.25

Plug in X to get the angle measure .

3 0

3 years ago

Read 2 more answers