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Alborosie
3 years ago
8

Suppose that y varies directly with x

Mathematics
1 answer:
Olin [163]3 years ago
8 0

Answer:

y=6

Step-by-step explanation:

x=20

y=10

x=15 > 20x=15

x=15/20

x=3/5

y=10(3/5)

=6

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Solve the given equation by completing the square.
klasskru [66]

Answer:

Step-by-step explanation:

x^2+8x=38\\\\x^2+8x-38=0\\\\\Delta=8^2+4*38=216=6^3\\\\x=\dfrac{-8-6\sqrt{6}  }{2} \ or\ x=\dfrac{-8+6\sqrt{6}  }{2}\\\\x=-4-3\sqrt{6} \ or\ x=-4+3\sqrt{6}\\\\a=-4\\b=3\\c=6\\

3 0
3 years ago
(7-15-3+5-7)×1 step by step​
Tresset [83]

Answer:

-13

Step-by-step explanation:

(7−15−3+5−7)⋅1

Subtract 15 from 7 to get −8.

(−8−3+5−7)×1

Subtract 3 from −8 to get −11.

(−11+5−7)×1

Add −11 and 5 to get −6.

(−6−7)×1

Subtract 7 from −6 to get −13.

−13

6 0
3 years ago
Read 2 more answers
A gold mine has two​ elevators, one for equipment and another for the miners. The equipment elevator descends 4 feet per second.
Ad libitum [116K]

Let d_m,\ d_e represent the depth of the miner and equipments elevator, respectively. We know that equipment elevator descends with a velocity of v_e = 4 feet per second, and the miners one descends with a velocity of v_m = 15 feet per second.

If we start counting time (t=0) when the equipment elevator begins to descend, after t seconds its depth will be

d_e(t) = v_et = 4t

On the other hand, the miner elevator follows the same rule, but we have to use its velocity, and remember that it starts with a delay of thirty seconds:

d_m(t) = v_m(t-30) = 15(t - 30)

Now, we have to wait the 30 seconds of delay, and then another 14 seconds. This means that we want to know the positions of both elevators when t = 44. Let's plug this value into the two equations:

d_e(44) = 4\cdot 44 = 176

d_m(44) = 15(44-30) = 15\cdot 14 = 210

So, the equipment elevator is 176 feet deep, and the miner elevator is 210 feet deep, and thus this is the deeper one.

7 0
3 years ago
Please help Please help
bekas [8.4K]
The answer is A. I looked it up for you on an surface area calculator.
5 0
3 years ago
Peace be upon you, please. I need help with this exercise now, please
baherus [9]
Okkkkkkkkk what do ya neeeeedddddd
4 0
3 years ago
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