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3 years ago

8

Pls answer plsssssssssssss

2 answers:

Anni [7]3 years ago

8 0

Answer:

duo october obito icky ick hating ick

Elden [556K]3 years ago

5 0

Answer:

It's 5

Step-by-step explanation:

14-9=5. It's obvious.

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Answer:

B

Step-by-step explanation:

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sergij07 [2.7K]

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3 years ago

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yuradex [85]

Answer:

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3 years ago

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kakasveta [241]

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Step-by-step explanation:

8 0

4 years ago

9. Stan’s Deli is situated inside a large industrial park. The weekday gross sales at Stan’s average $1,240, with a standard dev

mr Goodwill [35]

Answer:

0.9792

Step-by-step explanation:

Data provided in the question:

Average gross sales = $1,240

Standard deviation = $180

sample size = 40

Now,

standard deviation of sample average

= $\frac{\textup{Standard deviation}}{\sqrt{n}}$

= $\frac{180}{\sqrt{40}}$

= 28.46

Now,

z value for 1200 = $\frac{(1200-1240)}{28.46}$ = -1.4,

and,

p value for (z = -1.4) = 0.0808

therefore,

P(average < $1200) = 0.0808

Thus,

probability that the average over the next 40 weekdays will exceed $1,200

= 1 - 0.808

= 0.9792

7 0

3 years ago