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Arturiano [62]
3 years ago
11

How do I find the volume of the cylinder round to the nearest hundredths ​

Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

Volume = 502.65 cm³

Step-by-step explanation:

V= 3.14×4²×10 = 502.65 cm³

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I hope this helps you

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4 years ago
I NEED HELP PLZ, PLZ, I NEED HELP, I AM BEGGING YOU
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Answer:

tn = 8n -7

Step-by-step explanation:

given : t2=9, t4=25

the formula is:

tn = t1 + (n-1) d

gonna find d first:

d = (25-9) /(4-2) = 16/2 = 8

and find tn1:

t1 = 9-8 = 1

so, tn = 1 + (n-1) (8) = 1 +8n -8

tn = 8n -7

8 0
3 years ago
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1/8(16m−8)−17 simplified is
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1/8(16m−8)−17

distribute

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2m -1 -17

2m-18

Answer: 2m-18

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3 years ago
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A plan for a park has a rectangular plot of wild flowers that needs to be enclosed by 54 feet of fencing. Only three sides need
Gekata [30.6K]

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

a) What is the largest area possible for the garden?

Now, let the length of the rectangular plot be 54 -2x,

and the width of the rectangular plot be x,

so that:

\begin{gathered} \text{Area = (54 -2x) x = 54 x -2x}^2 \\ \frac{dA}{dx}=\text{ 54 - 4x = 0} \\ We\text{ have that:} \\ 54\text{ = 4x } \\ \text{Divide both sides by 4, we have that:} \\ \text{x = }\frac{54}{4} \\ \text{x = 13. 5} \end{gathered}

Then, the largest area possible for the garden will be:

\text{Area = 54x -2x}^2=54(13.5)-2(13.5)^2=729-364.5=364.5ft^2

b) What width will produce the maximum area?

Width,\text{ x = 13. 5 fe}et

c) The length of the garden that will produce the maximum area:

\text{Length = 54 - 2x = 54 - 2( 13. 5) = 54 -27 = 27 fe}et

5 0
1 year ago
What is 1.234 + .58 + 5.316 ?
marin [14]

Answer:

7.13

Step-by-step explanation:

8 0
2 years ago
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