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3 years ago

Find the midpoint of the line segment with the given endpoints. please help !!

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

7 0

Answer:

A. $(-3, -2)$

Step-by-step explanation:

Given:

(4, -10) and (-10, 6)

Required:

Midpoint of the two endpoints

Solution:

Apply the midpoint formula,

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Where,

(4, -10) = (x_1, y_1)

(-10, 6) = (x_2, y_2)

Plug in the values

$M(\frac{4 + (-10)}{2}, \frac{-10 + 6}{2})$

$M(\frac{-6}{2}, \frac{-4}{2})$

$M(-3, -2)$

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Ksivusya [100]

If you increase a number by 4.5%, then you're adding 4.5% of that number to 100% of that number. So essentially you just multiply 14187.13 by 104.5%, or 1.045 to find the answer, which is 14,825.55.

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3 years ago

True or False?<br> If, |al = |b|, then either a = b or a = - b

never [62]

Answer:

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Step-by-step explanation:

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3 years ago

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Maksim231197 [3]

Answer:

Step-by-step explanation:

x- int

1/3x - 2/3 = 0

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3 years ago

If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),

Anna007 [38]

Answer:

a = 3

b = 2

c = 0

d = -4

Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

28 = 8a + 4b + 2c + d

-20 = -8a + 4b - 2c + d

8 = 8b + 2d

d = 4 - 4b

Equation (2)

c = -a + b + d + 5

c = -a + b + 4 - 4b+ 5

c = -a - 3b + 9

28 = 8a + 4b + 2c + d (1)

28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b

28 = 6a - 6b + 22

6a - 6b = 6

a - b = 1

a = b + 1

220 = 64a + 16b + 4c + d (3)

220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b

220 = 60b + 100

60b = 120

b = 2

a = 2 + 1

a = 3

c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

8 0

3 years ago

Read 2 more answers

The proportion of American births that result in a birth defect is approximately 1/33 according to the Centers for Disease Contr

faltersainse [42]

Answer:

c. binomial distribution with n = 5 and p = 1/33.

Step-by-step explanation:

For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability of a birth resulting in a defect is independent of other births. So we use the binomial probability distrbution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The proportion of American births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).

This means that the probability of a birth resulting in a defect is $p = \frac{1}{33}$

A local hospital randomly selects five births.

This means that $n = 5$

So the correct answer is:

c. binomial distribution with n = 5 and p = 1/33.

8 0

3 years ago