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Andrew [12]
3 years ago
5

15.7 is what percent of 7852

Mathematics
1 answer:
abruzzese [7]3 years ago
3 0
The answer is 1232.764
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4. Bryce has 220 feet of fencing that will enclose a rectangular corral. One side of the corral will be 48 ft long. What will be
RideAnS [48]

Answer:

The area of the rectangular coral = 2,976 ft²

Step-by-step explanation:

Bryce has 220 ft of fencing to fence a rectangular coral.

Let the dimensions of the corral be x ft. × y ft.

One side of the coral is 48 ft. long

A rectangle has 4 sides, with each of the two opposite sides with the same dimension. Hence, the perimeter of the rectangular coral = 2(x + y) = 2x + 2y.

Total length of material for fencing = 220 ft.

Hence the perimeter of the reef = 220 ft.

2x + 2y = 220

And one length of the rectangular coral = x = 48 ft.

We can solve for the remaining dimension of the rectangular coral this way.

2(48) + 2y = 220

2y = 220 - 96 = 124

y = (124/2) = 62 ft.

Hence, the area of the rectangular coral = xy = 48 × 62 = 2,976 ft²

Hope this Helps!!!

7 0
4 years ago
Read 2 more answers
If <3=70°, then find the rest of the angles.
Sati [7]

If <3=70°, then find the rest of the angles.

3/4

5/6

7/8

79

1.) m<1=

2.) m<2=

4.) m<5=

3.) m<4=

6.) m<7=

5.) m<6=

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6 0
4 years ago
Can you tell me the answer? E = ?
Travka [436]

Answer:

E=mc^{2}

Step-by-step explanation:

An Albert Einstein iconic math problem.

3 0
3 years ago
If p(a|b) = 0.35, p(b) = 0.75 and p(a) = 0.44 are the events a and b independent ?
MatroZZZ [7]
Hello : 
note 1 : 
 p(A|B) = p(A∩B)/<span> p(B)

note 2 : 
</span> A and B independent: p(A∩B) = p(A)×p(B)
calculate : p(A∩B)
p(A∩B) = p(A|B)×p(B)
p(A∩B) = 0.35 ×0.75 = 0.2625
but :  p(A)×p(B) = 0.44×0.75 = 0.33
 conclusion : 
<span>the events A and B  are not  independent ?</span>
6 0
3 years ago
The side of a square is 2.5 cm. Find its perimeter and area.​
Neko [114]

Answer:

Perimeter = 10 cm

Area = 6.25 cm²

Step-by-step explanation:

\bf \: Given :

\sf \: Side  \:  of \:  the \:  square = 2.5 \: cm

\bf \: To \:  find:

\rightarrow \sf \: Perimeter

\sf\rightarrow Area

\bf \: Solution :

\rm \: First \:  w e \:  need \:  to \:  find  \: out  \: the  \: perimeter \:  o f \:  it.

So to find the Perimeter of the square, we'll use this formula :

\boxed{  \sf\longrightarrow \: Perimeter = 4 \times side}

\bf \: Step  \: 1 : \rm \:  Put \:  the  \: value  \: of   \: side \:  of \:  the  \: square :

\sf\longrightarrow \: Perimeter = (4 \times 2.5)cm

\bf \: Step\;2 : \rm Multiply :

\sf\longrightarrow \: Perimeter  = 10 \: cm

Hence, the perimeter would be 10 cm .

\rule{225pt}{2pt}

\sf \: Now,\; let's\; find  \: the  \: Area .

We know that the formula of Area to find the square is,

\boxed{ \sf \longrightarrow \: Area = (side) {}^{2} }

Note : The answer would always be in cm².

\bf Step\;  1  :\rm Put\;  the\; value \; of\;  side \; of \; the\; square :

\sf\longrightarrow{Area} = (2.5) {}^{2}  \: cm {}^{2}

\sf\longrightarrow{Area} = (2.5 × 2.5 ) \: cm {}^{2}

\bf \: Step\;2 : \rm Multiply :

\longrightarrow\sf \: Area = 6.25 \: cm {}^{2}

Hence, the area of the square would be 6.25 cm².

<em>We are done !</em>

\rule{225pt}{2pt}

I hope this helps!

Let me know if you have any questions.

:D

3 0
3 years ago
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