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2 years ago

Find the volume of the hemisphere below leave your answers in terms of pi

Mathematics

1 answer:

Ainat [17]2 years ago

7 0

Answer:

volume of the hemisphere

$\frac{2}{3} \times \pi \times {r}^{3} \\ \frac{2}{3} \times \pi \times 1331 \\ = 887.3333333333\pi$

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Moore's law says that the number of transistors in a dense integrated circuit increases by 41, percent every year. In 1974, a de

Lilit [14]

Answer:

5000(1+0.41)^5

Step-by-step explanation:

did the khan academy

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3 years ago

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eight hundred ninety-one billion, nine hundred sixty-two million, one hundred seventy-two thousand, four hundred nine in standar

ahrayia [7]

Answer:

891,962,172,409

Step-by-step explanation:

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3 years ago

Find the product for 1.29 x 5.4<br><br> show work please <3.

Afina-wow [57]

Answer:

6.966

Step-by-step explanation:

•Mark how many you have in the d.p

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3 years ago

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Suppose that prior to conducting a coin-flipping experiment, we suspect that the coin is fair. How many times would we have to f

BabaBlast [244]

Answer:

153 times

Step-by-step explanation:

We have to flip the coin in order to obtain a 95.8% confidence interval of width of at most .14

Width = 0.14

ME = $\frac{width}{2}$

ME = $\frac{0.14}{2}$

ME = $0.07$

$ME\geq z \times \sqrt{\frac{\widecap{p}(1-\widecap{p})}{n}}$

use p = 0.5

z at 95.8% is 1.727(using calculator)

$0.07 \geq 1.727 \times \sqrt{\frac{0.5(1-0.5)}{n}}$

$\frac{0.07}{1.727}\geq sqrt{\frac{0.5(1-0.5)}{n}}$

$(\frac{0.07}{1.727})^2 \geq \frac{0.5(1-0.5)}{n}$

$n \geq \frac{0.5(1-0.5)}{(\frac{0.07}{1.727})^2}$

$n \geq 152.169$

So, Option B is true

Hence we have to flip 153 times the coin in order to obtain a 95.8% confidence interval of width of at most .14 for the probability of flipping a head

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2 years ago

two parallel lines are graphed on a coordinate plane.how many of the lines could represent proportional relationship?Explain.

soldi70 [24.7K]

It's not necessary that either one represents a proportional
relationship. But if either one does, then the other one doesn't.
They can't both represent such a relationship.

The graph of a proportional relationship must go through
the origin. If one of a pair of parallel lines goes through
the origin, then the other one doesn't. (If two parallel lines
both went through the origin, then they would both be the
same line.)

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3 years ago

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