That would be negative 2 because when you add to a negative the number after the negative goes lower but the value is higher.
Length of the diameter = sqrt ( (-12- (-8)^2) +(2-0)^2) )
= sqrt (16 + 4) = sqrt20
so radius = sqrt 20 / 2 = sqrt5
so r^2 = 5
Center of the circle = coordinates of the midpoint of the diameter =
-8-12/2 , 2-0 / 2 = (-10, 1)
(x - a)^2 + (y - b)^2 = r^2 is general form of a circle so here the circle is:_
(x + 10)^2 + (y - 1)^2 = 5 Answer
Its B
The resolvent is:
x = (- b +/- root (b2 - 4ac)) / 2a
To apply it we must have a polynomial of the form:
ax2 + bx + c = 0
Where,
One side of the equation is zero.
The polynomial must be only grade 2.
The coefficient a must be different from zero.
Answer:
options: B, C, D are correct
Let x,y be the two numbers.
Given that one number is 8 greater than another.
Let x be the smaller number ans y be the greater number.
That is y=x+8. Let this be the first equation.
And also given that product of the two numbers is 84.
That is x × y = 84, let us plugin y=x+8 here.
x × (x+8) = 84
x²+ 8x -84 = 0.
x²+12x-4x-84 = 0
x(x+12)-4(x+12) =0
(x-4)(x+12)=0
That is x= 4 or -12.
<h3>If x=4 , y= 4+ 8 = 12</h3>
<h3>If x= -12, y= -12+8 = -4 </h3>
Hence two positive numbers corresponding to given conditions are 4,12.
And two negative numbers corresponding to given conditions are -12,-4.
Step-by-step explanation:
hope it may help you!!
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