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Using f(x) = y, we know that a graph of the function contains the (x,y) points (2,5) and (6,-1). first find the slope of that line,
m = (y2 - y1)/(x2 - x1) ⇒ -6/4⇒-3/2
then using either point (I'll use the first one) solve for b in y = mx + b.
5 = (-3/2)(2) + b⇒ 5 = -3 + b⇒ 8 = b.
So y = (-3/2)x + 8 ⇒ f(x) = (-3/2)x + 8.
Decimals that contain a zero in the tenth position can be thought of as a fraction over 100 as the tenth isn't occupied and the hundredth correlates to the 100 as a denominator. The same goes for a number with the tenth position occupied. These decimals would be put over 10 as they are occupying that position in the decimal.
Answer:
The vertex is [3,0]
Step-by-step explanation:
y=a(x−h)2+k , where ( h,k ) is the vertex of the parabola. By comparing the two equations, we see that h=3 and k=0 . The vertex is at ( 3,0 ).
