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Nataliya [291]
3 years ago
15

Any suggestions or answers

Mathematics
1 answer:
Kaylis [27]3 years ago
7 0
The correct answer is (20,-50)
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Help me out now Please I'm stuck on this
Elena-2011 [213]

5x + 2(x + 1) ≤ 23

Distribute the 2.

5x + 2x + 2 ≤ 23

Combine like terms.

7x + 2 ≤ 23

Subtract 2 from both sides.

7x ≤ 21

Divide both sides by 7

x ≤ 3

8 0
3 years ago
The ratio of the number of people who own a cat to the number of people who own a dog is 5:7. If there are 12 more people who ow
topjm [15]

Answer:

30 people own a cat

Step-by-step explanation:

6 0
3 years ago
Write the pair of fractions 3/10 and 1/2 as a pair of fractions with a common denominator
spin [16.1K]
The commen denominator for 10 and 2 would be 10. so 3/10 will stay the same ... and now we change the 1/2 to a fraction that has its denominator as 10. so the new fractions would be ... 3/10, and 5/10.
7 0
3 years ago
Match each point label on the box it to its description.
Ahat [919]
A is the minimum value
B is the first quartile
The point with the line through it (next to C) is the median. 
The point to the outside of the box is the third quartile.
D is the maximum value.

Hope this helped.
4 0
3 years ago
The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a
liubo4ka [24]

Answer:

(x,y,z)=(1477, 1464, 1437)

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>
  • Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
  • Mr.A earns Rs6000

So, the equation would be

3x  +  5y - 4z = 6000

<h3>Case-2:</h3>
  • Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
  • Mr B neither lose nor gain meaning he has made 0₹

hence,

2x   - 3y  +  z = 0

<h3>Case-3:</h3>
  • Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
  • Mr.C earns 13000₹

therefore,

- x    + 4y  +  6z = 13000

Thus our system of equations is

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\end{cases}\\\begin{cases}2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

Now solve the equation accordingly:

\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}

Solving the equation for x and y yields:

\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

\implies z= \dfrac{217000}{151}

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

6 0
2 years ago
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