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goblinko [34]
3 years ago
15

I’ll mark you brainlist I’ll mark you brainlist

Mathematics
1 answer:
umka21 [38]3 years ago
8 0

Answer:

0

Step-by-step explanation:

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PLZ help solve !!!!!!!
Ivahew [28]
37 I think I’m not sure just saying a random number don’t trust me I just needed the points
4 0
3 years ago
Help: 10 points!! 13=n+ 3/fourths
disa [49]

Answer:

n = 12 1/4

Step-by-step explanation:

do you need me to explain it too? I can! XD ^_^

6 0
3 years ago
What is the following product?<br> 15<br> 2<br> 0<br> 0<br> 0<br> 200<br> 500<br> 100000<br> 0
finlep [7]

Answer:

0

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If f(x) = (x+1)-1<br> and<br> g(x) = x–2, what is the domain of Rx) = g(x)?
german

Step-by-step explanation:

f is (x+1)-1

and g (the next letter in the alphabet) is x-2

first for f

x+1-1 = x

Then we -2 for g

So every letter there o words is just 2 less than the previous letter like

h would be h= x-4

so r(x) is g which is x-2 and x which would have to be the remaining amount to get to the number

3 0
2 years ago
The lines shown below are perpendicular. If the green line has a slop of 2/5, what is the slope of the red line?
aivan3 [116]

The slope of the red line that is perpendicular to the green line is: -5/2.

<h3>What are the Slope Values of Perpendicular Lines?</h3>

When one line lies perpendicular to another line, the slope of one must be the negative reciprocal of the other line.

<h3>What is the Negative Reciprocal of a Number?</h3>

If given a number, i.e. a/b, the negative reciprocal of a/b would the opposite value of the reciprocal of a/b.

Reciprocal of a/b is b/a. Negative reciprocal of a/b would therefore be: -b/a.

Given that the slope of the green line is: 2/5. And it is perpendicular to the red line. The slope of the red line would be the negative reciprocal of 2/5.

Negative reciprocal of 2/5 is -5/2.

Therefore, the slope of the red line is: -5/2.

Learn more about slope of perpendicular lines on:

brainly.com/question/1362601

#SPJ1

5 0
1 year ago
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