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3 years ago

If we work out the question ,

Mathematics

1 answer:

dybincka [34]3 years ago

4 0

Answer:

£5.40

Step-by-step explanation:

just add a zero for it to be pence

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What is 13/14+57/8 equally In fraction form

SpyIntel [72]

Answer:

8 3/56

Step-by-step explanation:

8 whole number, 3 over 56

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3 years ago

What is 90 by 25% decreased

viva [34]

Answer:

- 22.5

Step-by-step explanation:

Answer:

90 decreased by 25% = 67.5

Absolute change (actual difference):

67.5 - 90 = - 22.5

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2 years ago

Read 2 more answers

2sin^2 2x=2 In the domain [0, 2pi)

djverab [1.8K]

Please type this as 2(sin 2x)^2=2 2sin^2 2x=2 is confusing.

Reducing this expression: (sin 2x)^2 = 1

Taking the sqrt of both sides, sin 2x = plus or minus 1

If sin 2x = 1, then 2x must be pi/2 or 3pi/2, and so x must be pi/4 or 3pi/4.

Now you do this for sin 2x = -1.

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3 years ago

HELP ASAP f(x)=x² what is g(x)?

murzikaleks [220]

Just by comparing the plots of f(x) and g(x), it's clear that g(x) is just some positive scalar multiple of f(x), so that for some constant k, we have

g(x) = k • f(x) = kx² = (√k x)²

The plot of the transformed function g(x) = (√k x)² passes through the point (1, 4), which means

g(1) = (√k • 1)² = 4

and it follows that k = 4. So g(x) = 4x² = (2x)² and B is the correct choice.

4 0

3 years ago

Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +

GenaCL600 [577]

Answer:

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

Solution:

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3) ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2) ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)

On solving above equation for x

(x+6) (x+3) =2(x+3) (2x+2)

x+6 = 4x + 4

x-4x = 4 – 6

x = $\frac{2}{3}$

Dimension of pool A

Length = x+6 = ( $\frac{2}{3}$ ) +6 = 6.667m

Width = x +3 = ( $\frac{2}{3}$ ) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2( $\frac{2}{3}$ ) + 6 = $\frac{22}{3}$ = 7.333m

Width = 2x + 2 = 2( $\frac{2}{3}$ ) + 2 = $\frac{10}{3}$ = 3.333m

Verifying the area:

Area of pool A = ( $\frac{20}{3}$ ) x ( $\frac{11}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Area of pool B = ( $\frac{22}{3}$ ) x ( $\frac{10}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0

4 years ago