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Digiron [165]
3 years ago
7

How many words of five letters can be created that start with the letter T, contain 2 other consonats and end with 2 vowels? Not

e that a word is any combination of 5 letters but letters cannot be repeated.
Mathematics
1 answer:
Jet001 [13]3 years ago
8 0

If we're only counting 5 vowels (A, E, I, O, U) and 20 consonants (everything else, minus T), then there are

\dbinom52=\dfrac{5!}{2!(5-2)!}=10

ways of picking the vowels, and

\dbinom{20}2=\dfrac{20!}{2!(20-2)!}=190

ways of picking the consonants.

We want the word to start with T, and we'll allow any arrangement of the other 4 letters, so that the total number of words is

4!\dbinom52\dbinom{20}2=\boxed{45,600}

Keep in mind that this means words like TRIES and TIRES are treated as different.

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7 0
3 years ago
Read 2 more answers
Given m<br> 11 n, find the value of z.<br> +<br> (10X-14)<br> &gt;<br> (7x-8)
e-lub [12.9K]

Answer:

Solve

Let's solve your inequality step-by-step.

10x−14>7x−8

Step 1: Subtract 7x from both sides.

10x−14−7x>7x−8−7x

3x−14>−8

Step 2: Add 14 to both sides.

3x−14+14>−8+14

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Step 3: Divide both sides by 3

3x/3>6/3

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Step-by-step explanation:

Do your answers correctly or figure it out on paper

5 0
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