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Digiron [165]
3 years ago
7

How many words of five letters can be created that start with the letter T, contain 2 other consonats and end with 2 vowels? Not

e that a word is any combination of 5 letters but letters cannot be repeated.
Mathematics
1 answer:
Jet001 [13]3 years ago
8 0

If we're only counting 5 vowels (A, E, I, O, U) and 20 consonants (everything else, minus T), then there are

\dbinom52=\dfrac{5!}{2!(5-2)!}=10

ways of picking the vowels, and

\dbinom{20}2=\dfrac{20!}{2!(20-2)!}=190

ways of picking the consonants.

We want the word to start with T, and we'll allow any arrangement of the other 4 letters, so that the total number of words is

4!\dbinom52\dbinom{20}2=\boxed{45,600}

Keep in mind that this means words like TRIES and TIRES are treated as different.

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x=37.5 (not an integer)
If x=37 you get 37+38+39+40=154 and if x=38 you get 38+39+40+41=158[/tex]
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Equivalent expressions are expressions of equal values

The simplified expression of (3 - 4i) + (7 - 6i) is 10- 10i

The expression is given as:

(3 - 4i) + (7 - 6i)

Remove brackets in the above expression

3 - 4i + 7 - 6i

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Hence, the simplified expression of (3 - 4i) + (7 - 6i) is 10- 10i

Read more about equivalent expressions at:

brainly.com/question/2972832

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Help me please asap I need to know fully how to solve this problem
vivado [14]
Consider the absolute value, because we only worry about the quadrant later.

\text{Consider: } sin(A) = |-\frac{\sqrt{3}}{4}|
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Thus, we know that the hypotenuse has a length of 4 units, and the side opposite the angle, A is √3, because this is the nature of the sine function in relation to its triangular component.

The missing side can be found using Pythagoras' Theorem:
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Since angle A is in the third quadrant, the tangent function will produce a positive angle.

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tan(A) = \frac{\sqrt{39}}{13}
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