The length of the leach is 16.05 ft and the area of the mainsail is 64.94 ft²
<h3>What is application of law of sines?</h3>
The law of sines refers to the ratio of side length of triangle to the sine of the opposite angle which is same for all the sides.
SinA / a = SinB/ b = SinC/c
where, the A,B,C are the angles of the triangle and a,b,c are the opposite sides of the angle of triangle.
The mainsail foot is 13 feet long, the luff is 10 feet long has the length of the leach 6.93 ft and the area of the mainsail is 64.85 .
Part A; By using the law of sines;
SinA /10 = SinB / 13
SinA /10 = Sin54 / 13
A = 38.49°
C = 180 - (54 + 38.49)
C = 87.51°
So, Sin38.49 / a = Sin54/ b = Sin87.51/c
Sin38.49 / 10 = Sin54/ 13 = Sin87.51/c
c = Sin87.51 × 13 ÷ Sin54
c = 16.05 ft
Part B; Area of the mainsail = 1/2 × ab SinC
Area = 1/2 × 10 × 13 × Sin87.51
Area = 64.94 ft
Therefore, the length of the leach is 16.05 ft and the area of the mainsail is 64.94 ft²
Read more about the law of sines at; brainly.com/question/17289163
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Answer:
y=5g
Step-by-step explanation:
The answer would be 4.6 x 10^-5
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