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Sedbober [7]
3 years ago
5

A sporting goods store is having a 15% off sale on all items. Which functions can be used to find the sale price of an item that

has an original price of x? You may choose more than one correct answer.
ƒ(x) = x - .15x
Sale = Original - 15
ƒ(x) = 1.15x
Sale = Original - .15(Original)
y = .85x
Mathematics
1 answer:
asambeis [7]3 years ago
3 0
The answers are: 
<span>ƒ(x) = x - .15x
</span><span>Sale = Original - .15(Original)
</span><span>y = .85x

Let sale price be f(x) and x be the original price. Discount was 15% = 0.15
f(x) = x - 0.15x

If f(x) is sale and x is the original, then:
</span><span>Sale = Original - .15(Original)

Let sale price be y and original price x:
y = x - 0.15x
y = 1 * x - 0.15 * x
y = (1 - 0.15) * x
y = 0.85x</span>
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Kendra swims 126 miles in 3 days, what is the constant rate that Kendra swims per day? a. 40 miles per day c. 42 miles per day b
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5 0
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The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m
rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}

\text{Fuel used by 1st auto}=30 \text{ gallons}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}

\text{Fuel used by 2nd auto}=20 \text{ gallons}

Let us find the difference of fuel used by both autos.

\text{Number of gallons that 2nd auto used less than 1st auto}=30-20

\text{Number of gallons that 2nd auto used less than 1st auto}=10

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces 5\times 10=50 pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

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